Recent content by Gclip5

THANKS. Can't believe i didnt see that.

Yeah sorry about the poor labeling, but Nugso is correct. I still can't figure out a third equation to get.

I don't see the error. The voltage is dropping across the resistor from V2 to V3. Likewise for the other one ohm resistor from V2 to ground.

Homework Statement Find Vx. http://imageshack.com/a/img853/3093/ssdr.png Homework Equations NONE The Attempt at a Solution I just need one more equation so far I have: 1. V1 = 4v 2. V3 = 2Vx 3. (V1-V2)/2 = V2-V3+V2

Ok I'm using Snell's Law, n1 = 1 (its in air) and n2 = 1.289, if total internal reflection is required, then you can solve for the incident angle by φ = sin^-1(n1/n2). When you plug in n1 and n2 you get 50.877 degrees.

OHHHH, so the first angle is 30, and if I know the angle of incident, then i can just do 90 - 3) - 30 = 2) right? If I do that with the angle of incident i got (50.877 degrees), then I still don't get the right answer.

Yeah that's exactly where I'm not sure how to work them. I only know one of the three, the incident ray. RIght? Because when i use the critical angle calculation that's the angle I am getting.

Sort of... I assume the 2 and three have nothing to do with the φ2 and φ3? I don't get exactly what to get with them. Like i understand 3 would be 50.877 degrees right? And that 2 is the actual φ1 I need, but I don't get how to find the angle underneath 2 because if i get that one can't i just...

Homework Statement Red light is incident in air on a 30o - 60o - 90 o prism as shown. The incident beam is directed at an angle of φ1 = 37.6o with respect to the horizontal and enters the prism at a height h = 26 cm above the base. The beam leaves the prism to the air at a distance d =...