Yes, sulfur has 6 and chlorine has 7. You're going to need to understand why, or else your knowledge of chemistry will not develop much further. Look at the columns of the periodic table, for starters.
You've been given the theoretical yield of N2, and you know the actual yield from the experiment.
Percent yield = (Actual yield / Theoretical yield) x 100%
You can calculate this using moles.
Glucose is commonly stored as glycogen in the body.
More research on your part is required; this is a very generic and easily researchable question.
http://en.wikipedia.org/wiki/Glycogen
Oxidation is simply an increase in oxidation number. More practically, it is the loss of one or more electrons in a reaction. When the body converts complex molecules into simple ones (such as the oxidation of glucose), it often oxidizes those molecules.
More on oxidation...
Remember that a reducing agent reduces, and an oxidizing agent oxidizes. An agent that reduces can not in itself be reduced.
Draw out each half-reaction (including electron transfer) to determine which substance is oxidized, and vice versa.
I'd suggest taking a look here...
It appears to be written Mo6S9-xIx. In that case, the wire would contain x atoms of I and 9-x atoms of S.
For example, 6 I atoms would yield Mo6S3I6. It probably has to do with molecular packing.
Notice how in the first example, you've named the substance that was oxidized to be the oxidizing agent. In the second example, you named the substance that was reduced to be the oxidizing agent. Not only that, but you said chromium oxide was both reduced and oxidized.
http://en.wikipedia.org/wiki/Quantum_number#Single_electron_in_an_atom
If any of it is over your head, state what and how and we can explain it further.
The word you're looking for is amphoteric, which is a substance that can act as an acid or a base. Clearly, a substance with no H to donate cannot act as a Bronsted-Lowry acid, just as a substance that does not want/need an H will not act as a Bronsted-Lowry base. Amphoteric substances often...
Sorry I didn't reply to this sooner. For some reason, this thread did not show up to me as recently added to, so I only saw your post after calcnd replied.
You're generally correct about ionic bonds, although I did not understand your last sentence. If by farther up and right (i.e. more...
Do you need help classifying them, or do you just want answers? You won't get the latter. Show some work.
(1) text [ sub ] down [ /sub ] and [ sup ] up [ /sup ].
E.g. v02
(2) [ tex ] text_{down}^{up} [ /tex ]
E.g. v_{0}^{2}
You can click on the latter to see how someone created it.