Recent content by gingermom

Thank you! - it is why I tried to figure it out first - and you are correct I likely would have never thought of multiplying by (1-cos(x))/(1-cos(x)), although I remember coming across doing something similar ( different version of the equivalent to 1) to find the anti-derivative of csc(x), so...

Well my calculator gives me ln(1-cos(x)) + C

If I make sin(x) = u then dx= du/cos(x) then I have the ∫1/sin(x)dx + ∫1/u du=∫1/sin(x)dx +ln(u) but I am stuck at the integral for 1/sin(x)

I think I may have figured this out. substitute 1+cos(x) for U du = -sin(x) so that would be the integral of -u

Homework Statement ∫(1+cos(x))/sin(x) dx This is a multiple choice with the following options a. Ln|1-cos(x)| +C b. Ln|1+cos(x)| +C c. sin(x) +C d. csc(x)+tan(x) + C e. csc(x) +cot(x) +C Homework Equations The Attempt at a Solution ∫(1+cos(x))/sinx dx )...

Okay, I think I was making this way harder than it needed to be - since the integral is from -1 to x and the upper limit is not something like x^2, by the Fundamental Rule of Calculus I should just be able to substitute the x for the t. If the upper limit been a limit that involved a function...

so since the upper limit is x it would F '(x) =sqrt(1-x^2) * d/dx X which would be 1 so the answer would be F'(x) = sqrt(1-x^2) Is that right?

Oh, so F(1) would be the area of the semicircle - for C I will have to think on that - Would I find the antiderivative using substitution and then find the derivative of that? Will go back and review taking the integral with variable in the limits - thanks

Homework Statement for -1≤x≤1, F(x) =∫sqrt(1-t^2) from -1 to x ( sorry don't know how to put the limits on the sign a. What does F(1) represent geometrically? b. Evaluate F(1) c. Find F'(x) Homework Equations The Attempt at a Solution Since my teacher never seems to give...

Sorry for my comment - it is what I get for not paying more attention to the details - everyone's help is greatly appreciated

Well I guess I will know soon - since I turned in the corrected answer rather than my original post - guess that is what I guess for asking.

Thanks to all who responded. The question I had was how to get the 2√pi as the horizontal asymtotes from the data given. I now realize that erf(x) is not just an error but an actual function. Really hate it when they quiz us over "stretch stuff" that we had no real way of knowing. Extra thanks...

Thanks - I was thinking I needed to integrate the equation in order to determine the limit. I did graph f '(x) = e^-(x^2). If I graph that in the area for slope fields, I get similar slope field, but when I run through the tables it appears y is approaching .93 and that is not one of the...

Okay - I get the right side, but have never seen the er f(x). Is this problem overkill for high school Calc AB or have I really missed something. If I plug that is I get .999991, so would that make the limit 1?

Homework Statement This may not be the correct place to ask but the problem gives a graph of f'(x)=e^-x^2 with a particular solution f(0)=0. It then asks you to find the limit of f(x) as it approaches infinity using a graphing calculator options .886 .987 1.0 1.414 inf Homework...