Recent content by glasgowm

An electric cooker has two settings, high and low. It takes 1A at the low setting and 3A at the high setting (It lists 230 as the voltage on the diagram) Find the resistance of R1 & R2 (they are parallel circuits) V=IR (R= V/I) high setting: R=V/I ... R = 230V/3A = 76.6667Ω low setting: R=V/I...

uhh A = v-u / t is the only one I can think of but that doesn't involve distance? Here's what I done. --- distance / speed 20 / 15 1.3333s = t a = -15ms F = ma = 2400 * 15 = 36000N

2) Two cars, traveling in the same direction, skid on a patch of smooth, level ice Car A, of mass 1400kg skids straight into the back of Car B of mass 1000kg. The two cars join. immediatly before the impact car B was moving with a speed of 8ms Immediatly after the impact, both cars are moving...

I'm doing revision work from the beginning of the year and I can't find the formulas for these two questions. - 1) Calculate the velocity of the pellet before it strikes the putty 2) Calculate the average frictional force it takes for the car to come to rest if its traveling at 15ms and...

I already did that.

A cue exerts an average force of 7N on a stationary snooker ball of mass 200g if the impact lasts for 45ms, with what speed does the ball leave the que? --- Ft = mv - mu F = m(v-u/t) F = 0.2(v-0/0.0045) = 0.2v/0.0045 = 44.4444V Can't figure out what the next step is from my notes...

I asked you how to do it with the Friction and you just gave me F = ma is it 2000N - the friction = 1500N ?

So... A = f/m 2 = f/1000 F = 2000N ?

whats the formula that's like F = ma but with friction in it?

That didnt really help me :-/ The caravan is already accelerating at 2m.s-2, isn't it?

I just really don't understand the wording of this question. A car of mass 1200kg tows a caravan of mass 1000kg. The frictional force on the car and caravan is 200N and 500N respectively, The Car accelerates at 2 ms^-2 b) What force does the tow bar exert on the caravan? Does it want...

I found this on another site but can someone please explain it. Would that be (muzzle velocity)^2 / 2(gravity) Question A man fires a rifle of muzzle velocity 500ms at a fixed target 100m away. If the gun is pointing directly at the target, by how much does the bullet miss? My Attempt Time...

Bump, edited the last post a bit so that I might get some answers :-(

Yeah thanks all, was using the Horizontal component when I should of been using the vertical :-/ 2 more questions please :smile: 1) Can someone point me to a site that explains Horizontal and Vertical speed/time graphs. I've tried google but found nothing 2) How do I find the horizontal...

I don't get what you mean? :-/ Could you direct me to some notes or something...I've tried the ones from hsn.uk.net but I can't figure it out from them ---- Edit : thank you dmoravec, I tried that formula as well the first time but I was putting in the wrong numbers :-P