Recent content by GNelson

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    Calculus tangent line problem.

    One small issue the derivative should be 2x-4 should it not?
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    Percise defination of the limit of a sequence problem

    Homework Statement it is shown that lim n->Infinity of ln(n)/n=0 Find a natural number N such that n> N -> |ln(n)/n - 0| < 1/10 The Attempt at a Solution A sequence has a limit 0 if for every \epsilon>0 there exists a number N such that for every n > N |ln(n)/n-0|<\epsilon...
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    Sum of an infinite series(not quite geometric)

    My rational in the re-write was to write it in such a way that the terms of the sequence would be identical, in the orignal form we obtain 7/e^32+7/e^35 ect.. which was the only method of solution that I could see that had a chance of working. I tested each k value against f values at f=1...
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    Sum of an infinite series(not quite geometric)

    Homework Statement Determine the sum of the series: \sum^{infinity}_{K=10} \frac{7}{e^(3k+2)} Homework Equations The Attempt at a Solutionlimit n->infinity of sn=\sum^{n}_{K=10} \frac{7}{e^(3k+2)}=\frac{7}{e^(32)}+\frac{7}{e^(35)}...\frac{7}{e^(3n+2)} This series does not exactly fit a...
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    Epslion Proof for limit of a sequence

    And I got the problem thank you, However I am still curious about the derivation of N
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    Epslion Proof for limit of a sequence

    I am currently in calc II. I am curious where you got what we choose N= , I can finish it with the substitution you gave me. I am just curious how one derives it.
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    Epslion Proof for limit of a sequence

    Thanks guys working it through now.
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    Epslion Proof for limit of a sequence

    If i could evaluate it as a limit I would but its asking to prove it using the precise definition of a limit of a sequence, which means that is not an option
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    Epslion Proof for limit of a sequence

    Homework Statement Using only the definition of a limit of a sequence prove that lim n->infinity tanh(n)=1 Homework Equations The Attempt at a Solution My attempt at the solution is as follows. If 1 is the limit of the sequence then for every \epsilon>0, there exists an...
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