Recent content by GoodPost

Thanks all. I liked all the comments and I got more interested to move forward into this. :) Really I remember a lot from college about electronics; starting from semi-conductors physics up to tuned- and power- amplifiers by transistors and beyond. I believe I need to gather and guide my...

Hello all. I'm a guy with big interest into electronics. I have multiple ideas that want to realize in real devices but yet I have only my introduction course in electronics I studied in college as a background. As a first step I want to make an easy electronic device but I have no idea where...

It makes sense the way you interpreted it, but it's still confusing me since Rc=0 is actually assumed in the problem statement and if the resistance = 0 that means it's a short circuit, right? Plz check the attached photo. Thx.

The homework problem is pretty long and has different parts and I can do it. My only issue is what happens when a resistor (short-circuited) is connected to a reactance in parallel. It's more to understand a concept than to get an answer for a homework. As I know, if two resistors are...

Dears, Please help me out with this. The attached figure is an equivalent circuit of an induction machine. I'm trying to find the current (Is). It's assumed that the core losses are neglected and hence Rc =0. If this is the case, then Rc (short-circuited) is in parallel with jXm. What's the...

I'd connect the source to the secondary and measure V across the terminals of both sides. I may end up with a clue.

Exactly! So at the moment when we just release the ball, the net force along the tension axes is : T - mg*cos(theta) = m*ac = m*(v^2/r) = m*(0) = 0 And now the force "mg*sin(theta)" will cause the ball to move and so causing the velocity to increase. Hence, ac is changing too (increasing...

Is the velocity the same everywhere?

Hmm ... well, but we know that the centripetal acceleration, by definition, depends on the velocity, right?

^^ You're welcome, all the best wishes. G.P.

Hhhh ... I dunno, in my room the clock moves from left to right >< ... New voltage = voltage source + voltage across the resistor inside the cell. G.P.

Wow great here we go, I normally do conversions in two steps but this looks pretty simple and straightforward. Plus I'd like to add, 1 km = 1,000 m === (convert it into ft by the calculator ) 3280 ! Thanks, G.P.

Well, I know that feeling when the given quantity is in kilometers per hour and the result is required in feet per second! Anyway, you should work conversion problems as much as you can to get familiar with the conversions techniques. * Hmm ... by the way you have a scientific calculator...

Once you apply KVL over the loop, you'll figure out the current's value and its direction is COUNTER clock wise. Now, if you want to add two series voltages up, you simply need to add the values of these voltages up, BUT you MUST consider the polarities. In your case, Cell A: Since the...

SteliosVas, take a look over this code, I hope that it helps a bit. [FONT=Courier New]%clc %clear all [FONT=Courier New]x= 1:1:10; y= [ 0.841 0.909 0.141 -0.756 -0.958 -0.279 0.656 0.989 0.412 -0.544] Ytest = sign(y) a = y.^2...