Recent content by goonking

A pulley-and-shaft is connected to a motor which applies torque to spin the pulley as shown below: Now imagine someone jams machine by sticking a broom into one of the holes of the pulley. I would imagine there would be normal stresses at the hole (location of jam) and torsional stress on the...

you mean the "pi" terms? this book suggests using Buckingham pi theorem to find number of pi terms needed.

My book doesn't seem to clearly define "reference dimension", it states "Usually the reference dimensions required to describe the variables will be the basic dimensions M, L, and T or F, L, and T. However, in some instances perhaps only two dimensions, such as L and T, are required, or maybe...

lets say for example, the air drag (ϑ) that wind exerts on a tile is a function of the tile's width (w), height (h), viscosity of air (μ), density of air (ρ) and velocity of the air (V) then ϑ = f(w,h, μ, ρ, V) ϑ : MLT-2 w: L h: L μ : ML-1T-1 ρ: ML-3 V: LT-1 I understand there are 3 basic...

yes, that was my error, I thought I could take the a point as the origin, and just divide the problem into two separate ones, find the acceleration of both relative to the origin and just add up the vectors but that clearly isn't working out. I would need to find the acceleration of B relative...

Homework Statement Homework EquationsThe Attempt at a Solution First, I find the accelerations of each block, separate the accelerations into Y and X components and then add them as vectors. for B: B goes down the ramp with an acceleration of 3.35 m/s^2 X component : (3.35)(cos 20) = 3.15...

since the object is now sliding, kinetic friction is used: Fkinetic = 308.7 N Moment about G : -(308.7N)(0.45m) + (882N)(0.25) - (0.1) T = 0 T = 815.85 N therefore the max weight of C is 83.25 kg (I believe the extra 20 kg difference from my first attempt's calculation is enough to cause a...

Then I believe the acceleration caused by weight C has to be much greater than the deceleration caused by kinetic friction to cause a tipping while sliding?

there has to be a force that causes rotation of the body about an axis, but I'm not sure how to find the magnitude of force that will stop the sliding and cause a tipping.

yes, it will slide because I calculated static friction to be only 352 N.

Homework Statement Homework EquationsThe Attempt at a Solution When the barrel starts to tip, the normal at point A should be 0 Newtons, and then all weight would be on point B. I'm guessing if the barrel would tip, it wouldn't be sliding across the floor so kinetic friction is not used...

"Forward acting" friction is quite new to me, since usually most problems I've done include friction forces that are opposing the forward movement. But it makes sense, if one was on friction-less ice, one would need friction to move anywhere. Just quite hard to wrap my head around it.

Imagine a car race about to take place. A car is starting at rest and when the timer goes off, the driver steps on the gas. The car starts off so fast, that its front wheels rise upwards so that all the weight of the car is held up by the 2 rear wheels. The car travels this way for a few...

yes, this is much easier than the Yn and Yp stuff. I just need to connect the pieces to the puzzle.

(3,0) + C(1, 1/2)