Recent content by goosey00

Other ways we were doing similar problems is using either either nPr or nCr formula. Thats where I got this answer. Is that wrong?

Re: Linear Optimization Problem follow up So where do you get 54? BTW-you are right, it was suppose to be 1.

Linear Optimization Problem follow up Maximize: z=2x2+5x2+x3 x1+x2+x3 less then or equal to 12 x1-x2 less then or equal to 15 x2+2x3 less then or equal to 10 x1, x2 and x3 is greater then or equal to 0 x1= x2= x3= s1= s2= s3= z= I get x1=2, x2=10 x3=0 s1=0 s2=0...

I am not quite sure if I am using the correct formula. The problem is -A class of 30 students(12 male and 18 female) are put into groups of 3. How many combinations can be formed if the requirement is that no group can be entirely male or female? I get 4060 since it doesn't matter the order...

Before I get even more confusing, Ill just post the last part on my teachers blog. Thanks for the response. I really appreciate it.

93 to 60 after 13 min in a room of 25 degrees. how long before it gets to 40 degrees. Although this is a different problem I am stuck at the same point. so far I have .49295 (1/13) which I got .94704. Now what is it do I do now w/out graphing to get it?

got it now. Ok, so the last part of this question my professor said do not find the solution as the book says by graphing. The final part of the problem is take f(t)=22+68(.93859)^t. He said to do it the way we learned through exponential and the answer is 21. Again, I must be off since I am not...

The problem is 28/68=b^14 and I need to solve for b. I get .41176^14 which is not the right answer(which is .93859) What am I doing wrong?

Re: solve for f(x)a^x So it would be 4^2 so f(2)=16? right?

If you have f(x)=a^x and f(3)=64 what does f(2)=? Am I over thinking this one? Is it just f(2)=64 also?

I just can't remember how to put it in my calculator again. How did you get the .4387 to times by it-[FONT=MathJax_Math-italic-Web]e [FONT=MathJax_Main-Web]−[FONT=MathJax_Main-Web]0.38[FONT=MathJax_Main-Web]∗[FONT=MathJax_Main-Web]0.4387

Solve for x:e^-0.38x=.3 I got .4387 Is that correct

I did it by doing each separately and got it as I then divided it both out. So thanks, it worked..

Ti30x

I couldn't do the long way on the calculator. I think I can just break it down but to get your answer I was off 2 decimal places. Is that normal?