@Greg
I'm not sure if that was supposed to be sarcastic or not :-p
@MATLABdude
Yeah, I already have a tablet so it's just a hobby project.
Why would the hardware cost me much more than a tablet? They're priced at a minimum of 800USD a piece where I'm from.
So I have a project that I'm contemplating undertaking. What I basically want is:
A lot of the times I'm lying down on my bed and watching a show or something. Except I would rather my face be facing the ceiling than one of the walls, if that makes sense. So I'm trying to make a small device...
The Jython interpreter doesn't provide that much of an advantage since there's also the Cython and CPython interpreter.
The graph gets it's data from mining websites, doesn't that mean its not really applicable in this situation considering I'm not going to be doing much web-programming? But it...
Hello, everyone.
I've been learning how to code for a bit. I picked Python because I figured I'd be able to skip the issues I would otherwise have with syntax and focus more on the programming aspect of it.
Soon, though, I'm going to be ready to dive into one of the other languages with a...
Sorry if this has been said, already but I think we need to consider units.
If multiplication was repeated addition then:
If a and b had the units of 'm'.
a * b = a + kc
Would not tally dimensionally as 'kc' would have the same units as a, which is meters. Whereas (a*b) clearly has the unit...
Take my post with a grain of salt, I'm just a high school student.
To the extent of my knowledge, Classical Mechanics only quantifies gravity, and has no explanation as to the why and how.
General Relativity suggests that gravity is an effect of the curvature of spacetime around masses.
I'm not sure, I didnt read beyond the first line because I assumed the rest of your post built upon that formula, which was wrong.
Because Efficiency = Power (W) /Heat Generated (J)
So it the unit for efficiency would be s^-1.
Efficiency has no unit.
Total Energy remains constant so:
KE_Top + PE_Top = KE_y + PE_y
0 + mgh = 0.5mv^2 + mgy
mg(h-y)=0.5mv^2
2g(h-y)=v^2
v=(2g(h-y)^0.5
y=d-h
Therefore
v=(2g(h-(d-h))^0.5
=(2g(2h-d))^0.5
Is my best bet.
Coal burnt per second (A) = \frac{1.4}{60 * 60}
Power through coal burnt per second (P) = (43 * A)
P x Efficiency of engine (e) = 3.5kW
Find e. Be careful with the units and the conversion.
As a 17 year old, I feel unqualified to even begin giving you advice, so I will offer my opinion instead.
My dad has had to make some sacrifices in life which have affected him negatively. However, I also know that if he hadn't made those sacrifices, he wouldn't have felt as satisfied. At this...
Engineering. But I don't really care if what I study relates to the field.
And for what its worth, I enjoyed calculus the most throughout school, although that may be because it was the only close to challenging thing we did?
I like things where you need a creative step which makes everything...