Engine Efficiency: 1.4 kg Gasoline/hr = 3.5 kW Power

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The discussion focuses on calculating the efficiency of an engine that burns 1.4 kg of gasoline per hour and produces 3.5 kW of power, using a heating value of 43 MJ/kg. Participants clarify that efficiency is defined as the ratio of power output to heat energy input, emphasizing the importance of correct unit conversions. The calculated efficiency is approximately 0.209, which can be expressed as 20.9% for clarity. There is some debate about whether to present the efficiency as a decimal or a percentage. Ultimately, the consensus is that efficiency is a dimensionless ratio, with no specific units.
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Homework Statement


An engine burns 1.4 kg of gasoline per hour and yields 3.5 kW of power.

Homework Equations


Calculate the efficiency of the engine when the heating value of gasoline is 43 MJ/kg.

The Attempt at a Solution


Plz i just need the rule for engine efficiency.
 
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chawki said:

Homework Statement


An engine burns 1.4 kg of gasoline per hour and yields 3.5 kW of power.

Homework Equations


Calculate the efficiency of the engine when the heating value of gasoline is 43 MJ/kg.

The Attempt at a Solution


Plz i just need the rule for engine efficiency.

Coal burnt per second (A) = \frac{1.4}{60 * 60}
Power through coal burnt per second (P) = (43 * A)
P x Efficiency of engine (e) = 3.5kW

Find e. Be careful with the units and the conversion.
 
ok so:

efficiency = power generated/heat energy ?
and then:
power generated= 3.5kw
heat energy=mfuel*heating value

consumption per hour =mfuel*3600
mfuel=1.4/3600=3.88*10e-4 Kg/s

heat energy: Q= 3.88*10e-4*43=16.684kw

Efficiency= 3.5/16.684 = 0.209
 
chawki said:
ok so:

efficiency = power generated/heat energy ?
Not really.

Power of Engine = Efficiency of engine x Energy density of coal x Coal burnt per second
 
we would find same results, no?
 
I'm not sure, I didnt read beyond the first line because I assumed the rest of your post built upon that formula, which was wrong.

Because Efficiency = Power (W) /Heat Generated (J)
So it the unit for efficiency would be s^-1.

Efficiency has no unit.
 
in my work, efficiency has no unit.
it's kw/kw
 
chawki said:
in my work, efficiency has no unit.
it's kw/kw
You are correct. Efficiency is the ratio of energy output to energy input. This is the same as power output/power input.

AM
 
Andrew Mason said:
You are correct. Efficiency is the ratio of energy output to energy input. This is the same as power output/power input.

AM

Should we leave 0.209 as it is, or should we write 0.209*100% = 20.9% ?
 
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