Recent content by hansel13

I guess since there's 4 pairs in T^t and 4 pairs in A, we'd need 16 pairs to have full closure. thanks

So there are 16 elements in Tt?

Well I thought there are 12 elements in Tt. And 16 in A x A. But I guess if we add (0,0),(1,1),(2,2),(3,3) then Tt would have 16 elements as well?

Sorry, meant 12 elements in Tt I still don't follow. Why would {0,3} and {3,0} be the same? OK By definition: The transitive closure of T is the binary relation Tt on A that satisfies the following three properties: 1. Tt is transitive. 2. T is a subset of Tt. 3. If S is any other transitive...

4 pairs in A. So 8 in Tt? I still fail to follow...

Homework Statement T is a binary relation defined on A = {0, 1, 2, 3}. Let T = {(0,2), (1,0), (2,3), (3,1)} Find T^t, the transitive closure of T.The Attempt at a Solution I'm going to skip using commas cause it takes to long 02 23 = 03 31 10 = 30 23 31 = 21 10 02 = 12 12 23 = 13 02 21 = 01...

Sorry, cleaned up my notation. Got myself mixed up with another problem when I was writing up the problem. EDITED. And I understand now. I thought by 2n, we had 2n different sizes. I should have read the instructions better. so assuming we start on the leftmost peg... a1 = 2 (Move first...

Well a1 = 3 because When n is 1, we have 2 discs. There are 3 moves to get the discs to the other peg (1,2,1) And I have problems trying to figure the the recurrence relation, not sure how to find it from the information we are given.

The double tower of Hanoi puzzle contains 2n discs. There are n different sizes, two of each size. Initially one of the poles contains all the disks placed on top of each other in decreasing size. Discs of the same size are identical. You are allowed to place discs of the same size on top of...

OK thanks

Homework Statement A simple Pendulum is suspended from the ceiling of an elevator. The elevator is accelerating upwards with acceleration a. The period of this pendulum, in terms of its length L, g, and a is: 2\pi*(L/a)^(1/2) OR 2\pi*(L/(g+a))^(1/2) OR 2\pi*(L/g)^(1/2) Homework...

Homework Statement A person blows across the top of one arm of a U-tube partially filled with water. The water in that arm...? The answer is rises slightly: The water in that arm rises slightly. I really couldn't figure out why. Could someone help get me on the right track?

(16*radius*mass)^.5 = v But this leaves us with 2 unknown variables (mass and velocity)...

1/2 k 0.05^2 = 1/2 k 0.01^2 + 1/2 m v^2 V = (2/m*(1/2*10*.052 - 1/2 * 10 * 0.012 ))1/2 V = 2 Thanks :)

Let me see if I'm reading this right. The velocity from the spring is v = 2.04 m/s. So we could say that 1/5 of the velocity from the spring would be .2*2.04 = .408 And 2.04-.408 = 1.63, so the velocity is 1.63