Recent content by Havenater23

Okay, well if you take 4/10 you get like 0.4 hz then. Since you know the velocity = 12 m/s and you know the frequency then you can find the wavelength. The only thing is , you get an answer of like 30 m. If you look at that graph I find that almost impossible to correspond.

Homework Statement http://i213.photobucket.com/albums/cc285/havenater23/RIP.jpg?t=1301441030 I've been trying out things on this problem, I really need some help. I tried finding the frequency by counting the waves and dividing it by the seconds it takes through the waves. EX : 4 (Waves)/...

Homework Statement So I am doing this roller coaster lab in my physics class and I'm having some problems. You have to find the initial height of a hill and initial velocity; which was easy and I found this out. PEi = PEf+KEf m*9.8*h i = m*9.8*0.4572 + 1/2*m*(1.5m/s)^2 m's cancel assume...

Like 7761 m/s

Well I got the orbital radius by take the 225km + 6.38 * 10^6 m . Converting 225 km to m. I used that as the R in the problem to find the speed.

Homework Statement If the space station orbits the Earth 225 km above the surface , what are the satellites orbital speed and period ? The mass of the Earth is 5.97 E24 kg and the radius is 6.38 E6 m. Homework Equations The Attempt at a Solution I already have the speed ( v ) , I...

Okay I got the answer, but I don't think it's as long as I calculated. I got something like 2.05*10^25 I can see it being 2 years, but what am I doing wrong?

I need someone to check my work can you please solve this and tell me what you get? I have it set up like so t^2 / (500*10^6)^3 = 3.35*10^24

That the period of orbital is squared and that radius is squared, and this proportional between two planets , I believe ? So it would actually work with distances and period orbitals of other planets correct ?

How come ?

Average distance : 149.6 * 10^6 km Period : 1.0 Earth years

Homework Statement An asteroid is located between Mars and Jupiter. It is thought that a planet once orbited here but was somehow destroyed and broken up into small chunks(perhaps by getting hit by a comet or asteroid). If an asteroid in this belt has an average distance from the sun of 500 *...

Taking the Mass B * G = A(Mass B + Mass A)Mass B = 10g = 0.01 kg Mass A = 500G = 0.5 kg 0.01*9.8 = A ( 0.01 + 0.5) 0.098 = A 0.51 A = 0.19 m/s^2 Vf^2 = Vi^2 + 2 ad Vf^2 = o^2 + 2 0.19(1.50) Vf = 0.76 Then use this formula Vf = Vi + a T 0.76= 0+ 0.19(t) T= 4 seconds

For Mass A aka 500G the equation what setup like this : Ft=MassA * a (Orginally Ft-Ff=MassA * a ; til I knew to just forget friction) Mass B was set up like so : Mass B * G - Ft =Mass B * a Substituting Mass A for Ft : Mass B * G - Mass A * a = Mass B * a Arranged all acclamations on one...

Alright, well I got 4 secs technically 3.9 . If you could check it I would really appreciate it.