Man, that latex, it just looks beautiful, so I could have just said t(x)=cbrt(6x/k) and then substituted it into F(t)=mkt
which makes mk(6x/k)^1/3=(mk^(2/3))/(x^1/3)
Also, in Theodore's post, I'm confused as to what you said at the last part, I understand why dv/dt=(dv/dx)(dx/dt), but what did...