Recent content by hellothere123

oh, haha, i see now... THANKS A BUNCH!

well... for the top and bottom two.. i used.. sqrt[ (.07/2)^2 + ((.07/2)sqrt(3))^2 ] which is to the top corners.. so i thought it would be the same for the other corners so multiplied that by 4. then i have the ones on the sides which would be just .07 as the radius.

Homework Statement a regular hexagon with sides of length 7cm has a point mass of 1kg at each vertex. what is the moment of inertia for rotation about an axis which goes through the center of the hexagon and is perpendicular to the place of the hexagon? note the sides are made of rods with...

ok thanks a lot! i ask if it was right because i am unable to check my answer.

so i get 13.92 k is that right?

yes how do i find the uncertainty of the standard deviation itself. it could be a mistake on the teacher's part, but i just wanted to know if finding the uncertainty for the standard deviation was possible.

ok so since i have 4.3 i - 2.4 j how do i begin to find the torque and such?

My teacher is quite lazy and gave us a template. we are suppose to show our values and the estimates. but in the table there is a row for the standard deviations and we are suppose to put the best value +- the uncertainty. now he must have copied and pasted this for all the rows. Is there a way...

F = 1.5 i + 2.4 j N is applied at the point x = 3.0 m, y = 0 m. x = -1.3 m, y = 2.4 so the r displacement would be 3-(-1.3) i + 0-2.4 j so r would be sqrt( 4.3^2 + 2.4^2) ?

ok so F = 1.5 i + 2.4 j and x = -1.3 m, y = 2.4 i get -3.6 K and -1.95K so is it.. -5.55 k?

Homework Statement 1) A force F = 1.5 i + 2.4 j N is applied at the point x = 3.0 m, y = 0 m. Find the torque about the point x = -1.3 m, y = 2.4 m. I believe the lever arm should be the distance between the two points. but then the force that acts perpendicular to this is where i cannot...

yea.. you are right. but to my understanding.. isn't it to the height of the center of mass? so i would have thought i should include the .26 but i guess not.. thanks.

i will change the numbers slightly to match a different problem that i have the solution for so i can see where i went wrong. not much difference: A 320 kg motorcycle includes two wheels, each of which is 52 cm in diameter and has rotational inertia 2.1 kg·m2. The cycle and its 75 kg rider are...

so i thought i would multiply everything by 2 for each wheel, but still get it wrong.. am i doing anything else wrong?

Homework Statement 1) A 320 kg motorcycle includes two wheels, each of which is 52 cm in diameter and has rotational inertia 2.1 kg·m2. The cycle and its 73 kg rider are coasting at 82 km/h on a flat road when they encounter a hill. If the cycle rolls up the hill with no applied power and no...