I am designing DC-DC capacitive based charge controller for charging 12V battery using variable dc power supply and then with solar panel as input sources.This charge controller topology is step up boost converter so by using PWM variable duty cycle technique I made its output fixed at 12V but...
In this circuit I have seen current is very low.What's the reason that in capacitor based circuit current is low while in conventional DC-DC converter current is high in which inductor used as main energy storage element.
Homework Statement
I am working on solar charge controller for 12V battery..From solar panel 8 to 16V variable input goes to step up converter which will double available input voltage and then there would be some
circuit which will make output of converter circuit constant at...
Solar panel Vmax =16V but it is in standard condition as mentioned in its datasheet while in normal condition it is varying 8-13V and would be minimum as compared to mentioned one..that's why put doubler circuit.
Plus MPPT I am not doing right now as I studied so I found that for bigger system...
yes in place of resistive load I have to use 12V battery which will be charged through this charge controller from solar panel during day time..and after battery there will be dc load in parallel..so solar panel then voltage doubler then some stabilizing circuit which will provide constant 12V...
yes in place of resistive load I have to use 12V battery which will be charged through this charge controller from solar panel during day time..and after battery there will be dc load in parallel..so solar panel then voltage doubler then some stabilizing circuit which will provide constant 12V...
well Vs I used different 5,10,15 etc from dc power supply..while Vmax of available solar panel as mentioned in datasheet is 16.1V at standard condition.Right now I am using dc source as input while latter it will be replaced by two solar panel in parallel of total 40W..components selection...
I have attached main paper of this circuit in my previous thread "Integration of below expression" if you kindly look there.Some expression for load average and instantaneous voltage is given while for current and capacitors value I need equations like for boost dc-dc converter circuits whole...
That previous circuit of DC-DC converter which I previously sent in pdf file..need some help..there in paper voltage equation mentioned and experimentally I checked that voltage is doubling but its current on output is so low i.e. in mA..I need help that how to determine its load current...
I am working on simulation and calculation of solar charge controller for lead acid battery..I simulated two solar panel in parallel along with switched capacitor dc-dc boost converter which is basically voltage doubler and it is working properly but now I need 12V on output of this boost...
When I wrote these equations in separate lines in latex after compilation in pdf file they appear on same line then I put $$ before and after these equations to be in separate lines but it shows error.
∫ [T/2 to T] (A + Be^(−αt)) dt
= (At − B/α e^(−αt)) | [T/2 to T]
= (AT − B/α e^(−αT)) − (AT/2 − B/α e^(−αT/2))
= AT/2 − B/α e^(−αT) + B/α e^(−αT/2)
where A=Vme^{-T/2RLC2}
while B=[1-e^(-t-T/2)/rC2]*[1-e^(-T/2RlC2)]
But this is not required result as in eq(6)