Recent content by howt

Thank you very much for info, I was wondering why no1 bother to reply... The link somehow manage to show a picture on my computer. Well, the question have been solved by my friend. It is no longer a problem. Thank you again for telling me though

Homework Statement http://img3.imageshack.us/img3/2178/9b26f2dd8dd8a8686c9c8c2.th.png Homework Equations \vec{\upsilon}= \vec{\Delta} V / ( B d) \vec{\upsilon}= u E The Attempt at a Solution from the diagram , we have \vec{\upsilon} = 1.25*10^-5 V/(B)(0.001m) using the...

Thanks, the problem might be those constant... Side Note: I just realize I got a typo on the topic... crap

Yup, correct

The Centripetal force is going to equal the magnetic force. Note that w = v/r Centripetal force , F=m v^2 /r.. =m r w^2 And the magnetic force on the alpha particle is, F = B q v = B q w r m r...

Think about this situation, If you are are having the same accelerating in a heavy vehicle and a light vehicle. In which vehicle you are going to feel a stronger force? or it is the same?

it is not given... I don't think we need it to solve the question The formula of it doesn't involve any radius...

Part a and b seems correct, well done.. You already figure out the net force on dragster, using F=ma. Part c is the same deal, but what do you think be sensible value to insert as m ? Is it affected by the mass of the dragster? You should be able to figure the answer

Homework Statement An alpha particle is moving at constant speed in a circle, perpendicular to a uniform magnetic field, making a revolution every 60 nanoseconds. Its speed is non-relativistic What is the numerical magnitude of the magnetic field in T ? Homework Equations alpha...

You will experience acceleration and deceleration during the ride. Thus, you should be considering The second law of motion

From F=k|s| You should get 62.5N with this, check your calculation. Note that This is not linear motion. You should be using the Centripetal force of Circular motion to find the answer, in which F=(mv^2)/r.