Recent content by hydrogen1

(delta H)/(delta H)s= the efficiency where subscript s means the delta H for the isoentropic process this is a definition of efficiency.

y is the concentration of the output stream always. Which is also the concentration in the tank always in a mixing process. y always represents the concentration inside the tank and x does not. See what I mean?

Ok, thanks this is now clear to me. The force applied - the weight of the object goes to kinetic energy

Yeah, I understand that one phase of one component means two state functions will fix all others. So what I'm saying is P1,V1 defines state one and P2,V2 defines state two. I feel like U1 and U2 should be different then. However, they are not U2-U1=0. Is this just because the states are...

Maybe somebody can explain this to me and I will have a better understand of the Isothermal expansion problem. Here is what I know: [SIZE="4"]\DeltaU(T)=0 but internal energy is also a state function. So if I expand from P1,V1 to P2,V2 isothermally then how can internal energy not change...

Just like reading any other X-Y plot except you have composition on the x-axis and temperature on the Y axis. Find the point on the x-axis of the binary phase diagram that corresponds to the composition. It will be like 40%A or .4A (which is the same as 60%B in a binary system right?) by mass...

It is incorrect because dx/dt is not the accumulation of salt in the tank. dy/dt is.

The conditions of the medium(air) put a limit on the speed of sound at 346m/s. Whether the source is moving or not the sound will travel at 346m/s to a stationary observer.

Hey Nikstar, Filip Larsen and Borek are both right but maybe I can describe it to you this way. The velocity is dictated by the medium so if you move into the velocity of the waves V apparent increases. If you move away from the waves then Vapp decreases relative to your frame. For example...

Wouldn't I be putting in the work to change potential energy and giving the object kinetic energy too? I do understand that the potential energy is a state function

This is a problem that can be solved best with a basic energy balance on an open system(your compressor). rate of energy out - rate of energy in = W + Q \dot{m}(\DeltaH +\Deltau^{2}/2+g\Deltah)= W+Q W=work rate(power) Q=heat H=enthalpy at some T&P u=average fluid velocity(could be...

Hey guys, I understand that if you lift an object a short distance in the air that it takes work because you are moving against the the weight of the object through a distance. So the equation in my mind is W=mgdcos\Theta where \Theta=0. But what I can't figure out is what if I lift the object...