oh whoops, i c
omg, can't factor...
(x^2 + x^4 + x^6 + x^8)^k
= [ (x^2) (1 + x^2 + x^3 + x^4 +...) ]^k
but 1 + x^2 + x^3 + x^4 + ... does not equal 1/(1-x)
cuz 1/(1-x) = 1 + x + x^2 + x^3 + x^4
Thanks guys, I now know i can do enumerative combinatorics but can't do algebra or...