Ok, so ##T+m_2g=m_2a,##
or
##T=m_2a-m_2g.##
So, correct me if I'm misunderstanding what you're saying, does that mean that ##mg_x## should actually be subtracted, making ##F_{net_{m_1}}=T-F_f-mg_x##?
I derived tension ##T## by applying ##F=ma## and getting ##T=ma## since ##T## is a force. I saw that since the mass of ##m_2## is given and its downward acceleration ##a## is given and on the same axis as ##T## (the ##y## axis), I could plug those into the force equation and get the tension...
Homework Statement
Two masses ##m_1## and ##m_2## are connected by a massless cord and a pulley, on a rough ramp, tilted at angle ∅ The pulley is massless and frictionless. The coefficient of kinetic friction between the ramp and m1 is ##μ_k.## Derive an expression for ##m_1,## given that...
Homework Statement
"An athlete executing a long jump leaves the ground at a 30.0° angle and travels a horizontal distance 8.00m. What was the take-off speed?"
Let
##x=## horizontal distance
##v=## velocity
##a=## acceleration
Known:
##x=8 m##
##x_0=0 m##
##a_y=-9.8 m/s^2##...