Recent content by Idealism_Theory

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    Calculating Time & Speed of Package Dropped from Plane

    Homework Statement airplane files horizontally with constant speed of 260 mph at an altitude of 500m. Ignore height of this point above sea level. Assume acceleration due to gravity is g= 9.8m/s^2 After ejecting a package from the plane, how long will it take for it to reach sea level from...
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    Projectile motion of a tennis ball

    Well, I tried that. It was incorrect! Now what do you suggest. I definitely didn't see that as the answer either. v = sqrt vx^2 + vy^2 v = sqrt 11.1^2 + 17.8^2 v = 30 m/s (which is marked as incorrect)
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    Projectile motion of a tennis ball

    Well, does Vo the originally stated 21.0m/s? That would mean the final velocity is 38.8 m/s... still not making sense. Please clarify, someone! Originally Posted by Idealism_Theory Yes, I am completely stumped. If they're asking for velocity at highest point, naturally I'd think Vy. I...
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    Projectile motion of a tennis ball

    Yes, I am completely stumped. If they're asking for velocity at highest point, naturally I'd think Vy. I didn't think Vx could even have a "highest" point?! Only Vy has a velocity of zero. As for Vx, what could what could that possibly be? Here's what I'm thinking now... Using equation...
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    Projectile motion of a tennis ball

    Homework Statement A tennis player hits a ball at ground level, giving it an initial velocity of 21.0 m/s at 58.0 deg above the horizontal. What is the ball's velocity at the highest point? Homework Equations Vx=Vocos(theta) Vy=Vosin(theta) y=1/2-g(t^2)+Vy(t) V-Vo/a = t The...
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    How Does Rocket Motion Change After Engine Failure?

    Okay, so I feel as if I'm getting the cold shoulder here. I honestly do not understand regardless of answers which is why I indicated I wasn't intending on someone doing the work for me... Anyone else care to explain the logic in all of this?
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    How Does Rocket Motion Change After Engine Failure?

    When trying to solve a) .. I arrived at an incorrect answer using d=0(7.0s)+1/2(3.70m/s^2)*(7.0s^2). Not sure what else I could possibly use. I understand what is meant by no upward thrust since it fails. So, 9.8 m/s^2 was correct. The direction is definitely downward because of this. Still...
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    How Does Rocket Motion Change After Engine Failure?

    Okay... so I'm not sure where exactly to start with all of this. It seems to be a big problem with manipulating these equations for me. Can someone please make sense of this problem... I don't want the answer!
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    How Does Rocket Motion Change After Engine Failure?

    Homework Statement A rocket blasts off vertically from rest on the launch pad with an upward acceleration of 3.70 (m/s^2}. At 7.0 (s} after blastoff, the engines suddenly fail, which means that the force they produce instantly stops. a)How high above the launch pad will the rocket...
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