Thank you. Let me try again.
1. Once Bob's conducts his experiment, upon measurement, the system will collapse into one of its eigenstates which each have a probability of occurring. Since there is a certain probability of each state occurring, and each measurement could possibly result in a...
I have a question on my homework set and I'm not sure the principle behind it:
1. Alice measured an observable F (a matrix) and passed the measured system immediately to another experimentalist, Bob, who is going to measure another observable G. Alice claims that she can deduce the experiment...
Thank you very much for your response.
With the capacitor's impedance set to negative and the correct answer pops up.
What is the rule to determine whether an impedance is positive or negative?
Homework Statement
Homework Equations
phasor forms
voltage division
current division
The Attempt at a Solution
Using superposition, considering only the varying voltage source.
Z (L) = 4j
Z (C) = 5j
Total impedance:
4 is parallel with 5 = 2.44 + 1.95j
series with 1 + 4j
Total...
Homework Statement
Homework Equations
[/B]
Tao = R(th) C
The Attempt at a Solution
The unknown DC circuit model consists of a V(th) and R(th)
Tao = (R(th) + 3000) C , total resistance of circuit is R(th) + 3000
0.004 = (R(th) + 3000) (1x10^-6)
R(th) = 1 kOhm
The V(th) should oppose the...
Homework Statement
Homework Equations
V(oc) = I(sc) * R(th)
Kirchoff's voltage law
The Attempt at a Solution
a) is okay. For part b):
After redrawing with the R(th) and V(th) found in part a):
Equations of loops:
s is I(sc)
a is I(left loop)
left loop:
-8 + a(4000) + (a-s)(4000) = 0
right...
Homework Statement
Homework Equations
V = IR
Kirchoff's Voltage Law
The Attempt at a Solution
[/B]
Top loop - a
Bottom right - b
Bottom left - c
Ix = x
KVL:
top: a(6000) + (a-b)(2000) + 5x - 10=0
bottom right: -5x + (b-a)(2000) + b(3000) + (b-c)(4000) = 0
bottom left ...
Homework Statement
Homework Equations
emf = i (induced) R
emf = - d(Ф)/dt
Ф = B (dot) A
B = μi/(4piR)
The Attempt at a Solution
emf = - d(Ф)/dt
emf = - d( B (dot) A )/dt
emf = - d[ (μi/(4piR) * A ]/dt, A and B are perpendicular
Really not sure how to proceed from here as there are...
Homework Statement
Homework Equations
R = pL/A
The Attempt at a Solution
R(a) = 2x10^-4(0.15)/[pi(0.0005/2)^2] = 152.789 [Ohms]
It is slightly off. Is there a subtle point that I've missed?
Thank you very much.