Recent content by iiiiaann

any help here? I'm really stumped on this one

Homework Statement Homework Equations I know this is supposed to use Lenz's law, but I don't really understand it V=IR The Attempt at a Solution I calculated the resistance of the circuit to be 6.4e-6 / .0015 = 0.00426666667, but that's as far as i know what to do

Homework Statement Homework Equations this is what i think i figured out to be the equation for force as a function of θ: F(θ) = (μmg)/(cos(θ) + μsin(θ)) The Attempt at a Solution I tried to find extrema using the numbers given to figure out the angle, but the number i am getting is not...

i know that for f(x) to be a legitimate pdf, the integral from negative infinity to positive infinity of f(x) has to equal 1, but i don't know how that could help me find c in this situation

Homework Statement 1. The Beta distribution: A Beta random variable is a positive continuous random variable dened on [0; 1] that has two parameters associated with it, usually denoted  and . Both  and  must be positive real numbers. The beta distribution is used to model the...

got it, 0.000445358666. Thanks for putting me on the right track guys

C(E/2) = CE(1-e^-t/RC) 1/2 = 1 - e^-t/RC e^-t/RC = 1/2 -t/RC = ln(1/2) -t = ln(1/2) * RC t = -1 * ln(1/2) * RC t = -1 * -.6931 * 24 * 13e-6 = 0.000216 s = 0.216 ms Thanks again for the help, these forums (you especially) are fantastic

is it just the same equation except without the "1 -" part? so V0(e^-t/TAU)?

the charge is Q = CV which would be 13uF * E / 2

where do i go from here?

Homework Statement In the figure below, R1 = 13.0 kΩ, R2 = 18.0 kΩ, C = 0.600 µF, and the ideal battery has emf = 20.0 V. First, the switch is closed a long time so that the steady state is reached. Then the switch is opened at time t = 0. What is the current in resistor 2 at t = 4.00 ms...

Would it just be 1/2 E?

I'm not sure i follow what you are saying? Would the combination of the 2 be equal to E?

the charge on the capacitor would be Q = CV = (13e-6)(E) if the potential difference were E

Homework Statement Switch S in the figure below is closed at time t = 0, to begin charging an initially uncharged capacitor of capacitance C = 13.0 µF through a resistor of resistance R = 24.0 . At what time is the electric potential across the capacitor equal to that across the resistor...