Thank you for your taking the time to write a reply, Doc Al! :) I should warn you: I'm not good at understanding physics, but if I don't understand it, then unless a problem looks identical to the one before, I'm at a bit of a loss, so here's hoping that I can develop this "physical intuition."...
Hi! :) I'm confused about the direction of the friction vector when we decelerate and when we turn. I've memorized the directions (if I decelerate going east, friction is aimed west; if I am in a flat circle and going around it, friction points to the middle), but they don't exactly make sense...
I'm trying to learn the various equations of enthalpy with certain assumptions, but I couldn't understand where they came from. So, I tried to derive them myself, but now I'm lost beyond reason.
I'm getting confused between the various forms of the enthalpy equation, depending on constant...
Thank you all for your replies: I'm getting closer in understanding!
Right! :D The area under the PV curve is equal to the work done: I do get that. What I didn't get was why the second curve (for the compression) is a different curve than the original one.
Thank you, Andrew Mason: I now...
So, I'm studying for the MCAT. There..I've said it. :) But, it's not a homework question: I just don't understand the concept.
My study book's thermodynamics section includes a very rough sketch of a heat engine to describe the 2nd Law of Thermodynamics. A side note in the text says that if...
Ohhhhh, OK, right, right, right. We just went over those exponential curves today. That makes sense: it wasn't 16.67 amps at the very beginning.
Whew...all right; thank you!
~Ibrahim~
Energy delivered to that stored on the capacitor...the U = .5QV formula!
No: I just tried it and it worked!
This time, instead, I got .06 coulombs as the charge, twice the charge compared to my previous attempt.
I completely forgot about that one. But, out of curiosity, why did my initial...
Homework Statement
A flashlight uses 6.0J in 1.8ms (0.0018 seconds). First question: find the power. Got it: 3333W (3.3E3 with two sig figs, which is the accepted answer in the online system).
The real problem: find the capacitance if the flashlight uses 200V.
Homework Equations
Power =...
Oh, crap.
Friction is a non-conservative force: it depends on the path.
There are no conservative forces acting, only non-conservative (friction).
0J = 0J.
Got it. Thanks for the solution, however simple!
~Ibrahim~
Homework Statement
Work done by conservative forces = -\DeltaU
Homework Equations
Above.
The Attempt at a Solution
Here is the whole equation:
Wc+ Wnc = \DeltaK.
Wnc = \DeltaK + \DeltaU.
So, Wc = -\DeltaU.
But, for example, how does that apply in a situation with no...
Hmm...well, I actually don't speak Turkish. :(
From what Google Translate tells me, yeah, you're right. There aren't too many resources online which is the reason why I created this thread.
I would try looking through this thread. Is this for a homework assignment? What information do you...
Whoops, you're definitely right. :redface: It's a .05M solution that they took 25ml, not a .1M solution. Good call.
I guess you titrated it a bit too much because, even though they're close, I'm guessing that it has a K>1 so the equilibrium concentration would have been even lower...
:)
Ooh, yeah. :D Those sound good!
I did a project on boron neutron capture therapy a while back (it was legit made awesome by none other than folks here at PF!) and it was a way to bypass the blood brain barrier. Definitely very interesting stuff. Are you at a college? If so, you probably...
Oh, no, it's definitely OK. Another set of eyes always helps. :)
I think it took 25ml of a solution of a .1M Ag+/.1M Fe2+. So,
.100 mols/1000ml x 25ml = .0025mols of Ag+ initially, .0013mols @ equilibrium.
~Ibrahim~