Recent content by Illuminitwit

q0 = 4.2 E -6?

Is this approach correct? (F/kc)r^2 = q E = kc(q/r^2) ∆V = -Ed

E = Fe/q0

Homework Statement A man walks into an electric field with a small charged object that has a charged value of 4.2 E-6C. At a distance of 10m from the object that is responsible for the electric field, he notices a force of 8.0 N on the object he is carrying. What is the electric field...

Thanks again! That was a really helpful link. I'll start looking there and like places more often. Also, I'm sorry I've been posting several questions lately. It's just that I've essentially done almost an entire semester of Physics in three weeks after taking a whole year off of Physics...

I'm supposed to write a brief essay response to this question on my unit exam, and I don't exactly understand it. Please explain it to me, and then I can appropriately write the short essay. Thanks! Homework Statement "The energy companies use step-up transformers to send high voltage...

Just out of curiosity, what specifically, is the job you're trying to get by sleeping with this girl? Did you literally mean a job at a gold mine, or is that some sort of analogy term for another job? I'm just trying to find the connection to this thread and physics.

I have no idea... That isn't covered anywhere in my textbook or lessons. I'll see if I can figure it out, though... The voltage in the simulation is retarding voltage, I think... According to http://web.mit.edu/zchen/www/PHOTOELECTRICPAPERDRAFT.pdf, V(retarding) = (hf - phi)/e KE = hf -...

I found a website that has the listed work functions in eV for various metals regarding photoelectric effect. I just have to convert that using 1.6 x 10-19 J•s. So I'm set. Actually, it's pretty pathetic because it's not a "real" lab. It's considered a virtual simulation online and I have to...

Thanks! I didn't think voltage and current stuff was necessary... It isn't really about electrical circuits or anything, sooo... The three metals I have are Potassium, Calcium, and Uranium... Should I just look up the work function online?

Waiiit... Can't I just use the velocity of light in a vacuum? I mean, I'd have to assume the photoelectric effect in a vacuum, but I guess that'll work... Sorry to waste a post! Unless anyone has any extra advice. Thanks! :)

Homework Statement I have to calculate the frequency of incident light shot at a metal plate.Homework Equations I know the voltage, intensity, and wavelength. wavelength = velocity/frequency frequency = velocity/wavelength voltage = current • resistanceThe Attempt at a Solution There isn't any...

Good tip, and thanks for the help! Also, I noticed some of my mistakes from the original equations. The change in eV, as you said, was .1, whereas I had the numbers displaced by a factor of 10 with an extra zero to the right of the decimal. It kind of screwed up my powers... I think I...

∆eV = -.4 - (-.5) = .1 eV f = E/h f = (.1)(1.6 x 10-19) / 6.63 x 10-34 f = 2.4 x 1013 λ = c/f λ = 2.99 x 108 / 2.4 x 1013 λ = 1.24 x 10-5 Working backwards; λ = 4.35 x 10-7 4.35 x 10-7 = 2.99 x 108 / f 2.99 x 108 / 4.35 x 10-7 = f f = 6.89 x 1014 f • h = E f • 6.63 x 10-34 = ∆eV • 1.6 x 10-19...

4.35 x 10-7 = c/f c / 4.35 x 10-7 = f 2.99 x 108 / 4.35 x 10-7 = f f = 6.87 x 1014 f = E/h f • h = E 6.87 x 1014 • 6.63 x 10-34 = E E = 1.04 x 1048 1.6 x 10-19 / 1.04 x 1048 = ∆eV Oops... I'm sure I did something wrong... Do I at least have the right sort of idea? Or is my...