1. The problem statement, all variables and given/known data A man walks into an electric field with a small charged object that has a charged value of 4.2 E-6C. At a distance of 10m from the object that is responsible for the electric field, he notices a force of 8.0 N on the object he is carrying. What is the electric field intensity? What is the potential difference? 2. Relevant equations E = kc(q/r^2) F = kc(q1q2/r^2) ∆V = -Ed 3. The attempt at a solution F = kc(q1q2/r^2) 8.0 = 9 E9 • (4.2 E-6 • q2) / 10^2 800 = 9 E9 • 4.2 E-6 • q2 800/(9 E9 • 4.2 E-6) = q2 = 2.1 E-2 E = kc(q/r^2) E = 9 E9 • (4.2 E-6 / 10^2) E = 378 Round to two significant figures: E = 380 [Interesting, but unnecessary; F/E = q2] ∆V = -Ed ∆V = -380 • 10 ∆V = -3800 I think the first set of equations where I used F were unnecessary. The electric field intensity = 380 N/C. The potential difference is = -3,800 Volts. I really don't think I did this right. The numbers I ended up with look too large, and I don't know if volts are supposed to be negative. I don't understand what "q" is supposed to be. Is it the difference between q1 and q2? What's q0? Does it even have a real value? I went through all the material and it still doesn't make sense!