Hi Doc Al,
I am really sorry for the late response but I was so busy studying that i haven't been able to check the post.
THank you very much for your help, I finally got it (actually right now). I followed your steps and I am really thankful for your help.
I have tried this equation but I just seem to get -4000i+16000j. But this seems to be wrong.
Any further advice? I mean I substituted the final momentum from the initial momentum of A and divided by time, which however is initial momentum of B.
Doesnt make sense. Please help
Hi friends,
I am preparing for my exam and i am stuck with this problem, please help me out.
It won't take too long, I hope.
Homework Statement
Two bodies A and B have masses mA and mB respectively and collide completely inelastic.
Given that the mass of body A is 1200 kg and body B is...
Hello friends, I have a question considering Newton in circular motion.
Homework Statement
Six artificial satellites complete one circular orbit around a space station in the same amount of time. Each satellite has mass m and radius of orbit L.
What is the net force of every single...
Oh you´re right.
I wasn´t really considering the two in the middle they seemed not really "important" in the beginning. But now i understand that Block 1 has a bigger impact on block 2 than block 3 has on 2, and the other way round!
Well, thanks again.
Good morning alphysicist,
a)well I started thinking that most of the weight is on the 1kg block therefore the force that it puts on the floor must be equal to what the floor puts back on the block (N´s 3rd law).
b)However i wasnt really sure about the last one since I believed that the 3kg block...
Hello guys, I am currently busy with this introductory assignment on Newtons Laws.
I have tried to solve but i am not sure whether i have the right solution.
Please help.
Homework Statement
Three blocks are stacked on top of each other inside an elevator as shown in the figure.
Answer...
Thank you very much. I "could" have solved it using my brain since your explanation is so simple and true, I mean not having to depend on equations.
Well, thank you very much!
My goodness I solved it. I couldn't do it before because I was bringing the equations to the left hand side as well that's why i got my odd solution.
Now thanks to your advice i get 2/3 F.
So the force applied on the middle link by the upper one is 2/3 F. Am i correct?
I put those two equations together by replacing a with F-3mg/3m.
But what i get is mf=0.
So i am doing something wrong?
How else can i put these equations together?
Thanks for your help by the way-
Hello alphysicist, thank you for your response.
I figured since the first equation describes the chain which oncisist of the links i must break it down like you said, so:
m2*a2 = F/3 - m1*g
Is that correct? Thanks again
Dear all, I hope you could help me out a little.
Homework Statement
A person tries to raise a chain of 3 identical links; where each of the links has mass m.
The chain is connected to a string is suspended vertically with the person holding the upper end of the string and pulling upward...
Finally...
The answer i was lookin for is 20.21/2.
Thank you very much for your patience. It was really absurd because i was doing all the relativity questions with ease and then there comes a problem like this... :)
Thank you very much again tiny-tim!
Yeah.
I got the answer but I did it in a different way.
I separated the vector into its components vx and vy.
vx = 4 vy = 10.47
then: tan-1 = 4/10.47 = 20.something!
Thanks anyway!
I added 20.2 and tan-1 (20/57)!
Really could you please tell me how you did it and got your answer.
Because I have lost hope and i really need a light bulb over my head please.
Thank you really for your help.