Thanks for the replies everyone,
So as I understand it this accuracy is relative to the load applied? So with a 16kg load the accuracy would be 0.25% of 16kg = +-0.04kg or 0.02% of the full scale (200kg) load. Therefore with anything weighing more than 16kg this load cell is less accurate then...
Hi Everyone,
I've been trying to find a load cell for a report and I need one with a maximum capacity of >200Kg and and accuracy of 10 grams or better (used in compression). I've taken a look on the web and the highest accuracy I can find is about 0.03% of the maximum capacity; which with a...
Fair is proportional to v2
v is proportional to 1/t
Fair changes by a factor of 5.
So velocity will change by a factor of \sqrt{5}
And time will change by a factor of 1/\sqrt{5}
So your answer should be t = 45 x 1/\sqrt{5}
As the object travels downward the potential energy it had is converted to velocity. This is why the object will speed up at the bottom and slow down at the top.
Basically you take the change in height of the object, figure out how much potential energy was converted to kinetic energy over that...
But the height of the building does not change. Velocity = distance / time
Since the distance does not change the only thing that can alter velocity is time.
"because of the tightwalker jumping upwards then the Force from the tightwalker is slackened"
They want the tension as he jumps, before he leaves the rope.
Hint: The tightrope walker pushes down to jump up, putting more tension on the rope.
Just think what happens when the box hits the ground. It will stop but the mass on the spring will still have same velocity because nothing is stopping it. The only contribution of the fall on the system is an initial velocity. Hope that helps.
In this equation you have an inlet and exit temperature (T1 and T2). If you changed the pipe dimensions and velocities you would likely get a different exit temperature. If you were designing this system you would not know the exit temperature and your your equation for T2 would include pipe...
Wait a minute... hit another snag. To use that theorem I need to know what the mass of the missing hole is. I only know the mass of the disk as is (with the hole in it). Also the first formula I gave could only be used if I knew what the mass of the disk was with the hole filled in. This is...