Recent content by Indis Nenhrma

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    Internal resistance of a source

    Actually, I realized that it was an easy question. So, I solved it.
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    Internal resistance of a source

    Homework Statement A rule of thumb used to determine the internal resistance of a source is that it is the open-circuit voltage divided by the short-circuit current. Is this correct? Why or why not? thx for any help
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    The capacitance of the two metal sphere system

    thx dude.
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    The capacitance of the two metal sphere system

    Why did you choose limits as r and L-r?
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    Water as a dielectric in capacitors

    Thanks for your attention and expository answers. :)
  6. I

    The capacitance of the two metal sphere system

    I thought that I could solve this problem by integration. I can divide two spheres to small circular plates as parallel to each other and consider them as parallel plates. Then, i can add them up. It ain't difficult, but it requires calculus knowledge.
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    The capacitance of the two metal sphere system

    the capacitance of two metal sphere system Homework Statement What is the capacitance of the two metal sphere system. *The question has been attached shematically. All the variables are given in the attached file, there is no missing variable. thx for any help.
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    Water as a dielectric in capacitors

    "water" as a dielectric in capacitors Homework Statement Why do you think water is not commonly used as a dielectric in capacitors? K=80.4 *K=dielectric constant for water thx for any help