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Homework Help: Internal resistance of a source

  1. Apr 5, 2008 #1
    1. The problem statement, all variables and given/known data

    A rule of thumb used to determine the internal resistance of a source is that it is the open-circuit voltage divided by the short-circuit current. Is this correct? Why or why not?

    thx for any help
    Last edited: Apr 5, 2008
  2. jcsd
  3. Apr 5, 2008 #2
    Actually, I realized that it was an easy question. So, I solved it.
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