Well he his initial velocity before he hits the mud is 12m/s. So i tried figuring out the force he would be driving into the mud with. And from there I was going to calculate the effect of the coeffecient from his normal force. But since his mass wasnt given I am completely clueless. I have...
No. A 200lb barbell resting on a table would have the table exerting a 200lbs (x9.8) normal force back onto the weight. The ending result is no movement. Newtons first law: every object will stay at rest or constant velocity if no force acts upon it. So for a weightlifter to hold a 200lb weight...
Homework Statement
73) A cyclist is coasting at a steady speed of 12m/s but enters a muddy stretch where the effective coefficient of friction is 0.60. Will the cyclist emerge from the muddy stretch without having to pedal if the mud lasts for 11 meters?. If so, what will be the speed upon...
Force = mass x acceleration
1kg = 2.2 lbs, 200 lbs = 91kg
91 kg barbell resting on a scale on your hand without any movement will show 91 kg X 9.8m/s^2 netwons (equal to 891.8N or 91kg or 200lbs)
Now when you accelerate uniformly it at say 0.2 m/s the force will now become 91 kg x 10 Newtons...
Cant we eliminate mass from the equation? In other words in f(Normal) equals mg can't we just say 'a' or (v^2/r) instead.
How does this sound:
(9.8)(sin0)=(v^/r)
Homework Statement
If a curve with a radius of 88m is perfectly banked for a car traveling 75kn/h, what must be the coefficient of static friction for a car not to skid when traveling at 95 km/hHomework Equations
F=m(aR)
F(Normal) x sin0 = m(v^2/r)
The Attempt at a Solution
I've asked my...
Im going to college first year in sept for Mechtronics and I am reading in advance for electricity which i know is guna give me problems.
Right now I am stuck on this question. Dont tell me the answer but rather how if find it.
27) A 6V source is connected to a 100 ohm resistor by two 12...
Ok I am stuck on how to solve this problem and i don't have physics again until next week. The question is:
A ball is thrown horizontally at 22m/s from the roof of a building lands 36.0m from he base of the building. How tall is the building?