Homework question- kinematics in two dimension

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To determine the height of a building from which a ball is thrown horizontally at 22 m/s and lands 36.0 m away, first resolve the motion into horizontal and vertical components. Calculate the time it takes for the ball to travel 36.0 m horizontally using the formula time = distance/velocity. With the time determined, apply the vertical motion formula s = ut + 0.5a(t^2) to find the height, where s is the vertical distance, u is the initial vertical velocity (0 m/s), and a is the acceleration due to gravity. This approach will enable the calculation of the building's height. Understanding these kinematic principles is essential for solving the problem effectively.
Infamous_01
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Ok I am stuck on how to solve this problem and i don't have physics again until next week. The question is:

A ball is thrown horizontally at 22m/s from the roof of a building lands 36.0m from he base of the building. How tall is the building?
 
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What have you attempted so far?
 
ive tried nothing and I am all out of ideas
 
I can give you some hints. Resolve the ball's motion into the horizontal and vertical components.

For the horizontal component, you already have the initial velocity and the horizontal distance traveled (36.0m). Find the time taken for the ball to fall.

Now that you have this, use it for the vertical component. In the following formula:

s = ut + 0.5a(t^2)

s is the vertical height.

You should be able to solve your problem now. :)
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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