Recent content by inner08
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Choosing and finding limits of integration
I don't mean to sound dumb, but I'm not quite sure I know what you mean. Sorry. Maybe its just late :S- inner08
- Post #7
- Forum: Calculus and Beyond Homework Help
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Choosing and finding limits of integration
So it would simply be -2. Yes I do have the region drawn. So then I would have... int(-1,3) int(-2, -3/4x + 1/4) f(x) dA.?- inner08
- Post #5
- Forum: Calculus and Beyond Homework Help
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Choosing and finding limits of integration
I just thought..the slope starts at y=1 and then it goes downwards with the -3/4x + 1/4 slope till it reaches the point (3,-2).- inner08
- Post #3
- Forum: Calculus and Beyond Homework Help
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Choosing and finding limits of integration
Homework Statement For the given region R, find intR f(x) dA. The region has the following points: (-1,1), (-1,-2) and (3,-2) Homework Equations The Attempt at a Solution I'm having problems finding the boundaries for the integral. I know that we have: -1<=x<=3 and -2<=y<=1...- inner08
- Thread
- Integration Limits Limits of integration
- Replies: 7
- Forum: Calculus and Beyond Homework Help
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Phase difference and number of wavelengths
yep. I mean, I did translate it from French but I'm usually pretty good at it. It doesn't mention any sort of distance or anything. Just says "from point A to B". In regards to the phase difference: with the lense I found: 500nm without: 750nm so the phase difference is 750/500 = 1.5?- inner08
- Post #5
- Forum: Introductory Physics Homework Help
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Phase difference and number of wavelengths
I don't have the distance between both points. Is there a way to calculate it or just use a variable?- inner08
- Post #3
- Forum: Introductory Physics Homework Help
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Phase difference and number of wavelengths
Homework Statement A light wave is propagated from point A to point B in space. We introduce along the way a glass lens with parallel faces of index 1.5 and width L=1mm. The value of the wavelength is 500μm in space. How many wavelengths are between A and B with and without the glass lens...- inner08
- Thread
- Difference Phase Phase difference Wavelengths
- Replies: 5
- Forum: Introductory Physics Homework Help
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Convert the integral into polar coordinates
Ok, so theta is pi/4 so its from theta is from (0,pi/4). As for r, I'm still a bit confused. You said it has to go out of the circle so can I pick whatever I want like 3 or 4?..or how do I find it? Thanks for being patient with me.- inner08
- Post #8
- Forum: Calculus and Beyond Homework Help
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Convert the integral into polar coordinates
Ok. I drew a graph. From looking at it, r would be from 0 to 1 and theta from 0 to pi/2? By the way, shouldn't x=y and x=(4-y^2)^1/2 instead of x=(1-y^2)^1/2? If that is the case, r would be between 0 and 2 I think.- inner08
- Post #4
- Forum: Calculus and Beyond Homework Help
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Convert the integral into polar coordinates
Homework Statement Convert the following integrals into polar coordinates and then calculate them. a) int(0 , 2^(1/2)) int(y, [(4-y^2)^1/2]) xydxdy . Homework Equations x = rcostheta y = rsintheta r = (x^2 + y^2)^(1/2) The Attempt at a Solution Would it simply be: int(0...- inner08
- Thread
- Convert Coordinates Integral Polar Polar coordinates
- Replies: 10
- Forum: Calculus and Beyond Homework Help
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Expressing waves in complex form
Would anyone know any websites that could explain the idea behind this because my book is limited when describing this concept?- inner08
- Post #5
- Forum: Introductory Physics Homework Help
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Expressing waves in complex form
I think (not sure) that its: 1/2i(e^i (\theta) - e^(-i (\theta) ))- inner08
- Post #4
- Forum: Introductory Physics Homework Help
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Expressing waves in complex form
Question: Two waves have the same amplitude, speed, frequency moving in the same region of space. The resultant wave can be expressed like the sum of two waves: psy(y,t) = Asin(ky+wt) + Asin(ky-wt+pi). Express each wave individually using the complex representation. Demonstrate, using this...- inner08
- Thread
- Complex Form Waves
- Replies: 4
- Forum: Introductory Physics Homework Help
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Undergrad Optimization - find point by minimising squared distance
Find the point in the plane 3x+2y+z=1 that is the closest to the origin by minimising squared distance. (I hope I translated this ok..) I was thinking I would need to isolate a variable in the equation for the plane above then substitute it into the distance formula then do a partial...