thanks to that, now i have the right answer! but I'm still confused on the last sentence. i don't see why we should include 2.0 x 10^3 J into the transferred heat.
Homework Statement
Q = ?
ΔU = + 8.0x10^3
W = perhaps 0 since isovolumetric?
Energy Lost = -2.0x10^3
Mass of Water = 2.0 kg
Homework Equations
I'm stuck on this thermal dynamics problem. It states: "A 2.0 kg quantity of water is held at constant volume in a puressure cooker and...
Yes, I always draw a picture for my hardest questions. At the moment, I don't have a camera to take a picture of my work, however, I've created a little picture that imitates the work on my paper. Here it goes:
http://unityofthedragons.org/ex.jpg
This doens't include my answers because I...
I've figured out A... which asks for the work done by the flight attendant. I've looked up the three friction equations. I've tried solving C by using mu = fmax/fnormal ( mu = 40N / 70N ). And I've put a lot of thought into the two other equations, but they solve for the cofficient itself...
A question that I've spent hours on, but still can't seem to extract friction from it:
10.) A flight attendant pulls her 70.0N flight bag a distance of 253m along a level airport floor a a constant velocity. The force she exerts is 40.0N an angle of 52.0 Degrees horizontal. Find the...
Okay, so my question is: given the picture below, how can I find the area below the graph (in the shaded region) ? It's for a lab that I did in class, but it wasn't until i finished the whole picture that i realized that I didn't know how to calculate the area of this graph.
Thanks...
Hi guys, I'm a High School student seeking help. The regular physics help forum suspended my IP address from logging on for some reason, so no matter how many accounts I make, it won't let me sign in.
Okay, so my question is: given the picture below, how can I find the area below the graph...
Okay, so my question is: given the picture below, how can I find the area below the graph (in the shaded region) ? It's for a lab that I did in class, but it wasn't until i finished the whole picture that i realized that I didn't know how to calculate the area of this graph.
Thanks...