Recent content by iriver4

Homework Statement A light bulb is rated at 30 w when operated at 120 v. How much charge enters (and leaves) the light bulb in 4.0 min? ans is 17 C Homework Equations I = P/V i = dq/dt The Attempt at a Solution I = P/V = 30/120 = 0.25A q = I*t = (0.25)(4*60) = 60 C...

Thank you

So then the charge at the inner circle would be +2q and since the outer shell has a charge of q the charge outside would be equal and opposite giving us -q. Right ? Sorry I took so long have 4 finals to study for =/

Because the positive charge would induce a negative charge on the inner surface of the shell and the outer shell would have a positive induced charged. Thats how it was explained to me

Sorry this is another scenario where the conducting sphere has no charge. I want to know what happens if the conducting sphere has a charge of q. How does that affect the inner and outer charges ?

A spherical conducting shell with charge total q surrounds a charge –2q at the center of the shell. The charges on the inner and outer surfaces of the shell are respectively I know that if the conducting sphere has no charge the inner and outer charges would be +2q, and -2q respectively but...

What are the values for L' and W' ? I am really sorry but I tried infinite ways and I can't get the correct answer

He posted that A'(t) = W'L + L'W L = 60cm W = 40cm A'(t) = 0*60 + 0*40 = 0 Because the derivative of a constant is zero right ?

Thank you And would you be able to further explain how he got the problem ? I understand everything except how A'(t) is not equal to zero.

? How did you get A'(t) ? Isn't the derivative of a constant zero ?