i just don't understand how it can sink that far...
btw thanks for all the help, i really understand how to solve this type of question now, i appreciate it, thanks!
ok so since there's potential at the top and nothing(?) at the end, can i say
p(water)vg(d) = p(ball)vgh
1000(d) = 750(11)
d = .12 meters?
i really appreciate the help
or can i make an Fnet equation
like, mg - Fb = ma
p(ball)vg - p(water)vg = p(ball)*v*a
volumes cancle, so => 750(9.8) -1000(9.8) = 750*a
this yielding an acceleration of 3.267 m/s^2
would that be a correct approach, or is what i just laid out above incorrect?
Homework Statement
A small sphere 0.75 times as dense as water is dropped from a height of 11 m above the surface of a smooth lake. Determine the maximum depth to which the sphere will sink. Neglect any energy transferred to the water during impact and sinking.
for clarity's sake, I'm...
haha I've learned to never blame the calculator, blame the user ;]. it was my own careless arithmetic error that caused me to get the wrong answer. when i got down to 27.5625 i subtracted 1.8 kg instead of subtracting (1.8*9.8)N and so i got an answer that was too large.
thanks SO much for...
ok i did what you said. i obtained a v of .02756... and plugged that into Fb = 1000*(.02756...)*9.8, which gave me a Fb of 270.1125. I set this equal to mg and divided by 9.8 to get a final answer of 27.56. I then subtracted the 1.8 kg of wood and for some reason I'm wrong. Can you find my...
[SOLVED] i need help with a static fluids question
Homework Statement
A block of wood of 1.8 kg mass floats on water with 64% of its volume submerged. A lead block is placed on the wood and the wood is then fully submerged. Find the mass of the lead block.
Homework Equations
Fb =...