Recent content by islanderfan

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    Calculating Maximum Depth for a Sphere Dropped into Water

    i just don't understand how it can sink that far... btw thanks for all the help, i really understand how to solve this type of question now, i appreciate it, thanks!
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    Calculating Maximum Depth for a Sphere Dropped into Water

    or can i make h = 11+d? but when i did that i got a final d of 33 meters. this seems way too large to me
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    Calculating Maximum Depth for a Sphere Dropped into Water

    ok that makes sense, but won't that leave me with two unknowns?
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    Calculating Maximum Depth for a Sphere Dropped into Water

    ok so since there's potential at the top and nothing(?) at the end, can i say p(water)vg(d) = p(ball)vgh 1000(d) = 750(11) d = .12 meters? i really appreciate the help
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    Calculating Maximum Depth for a Sphere Dropped into Water

    or can i make an Fnet equation like, mg - Fb = ma p(ball)vg - p(water)vg = p(ball)*v*a volumes cancle, so => 750(9.8) -1000(9.8) = 750*a this yielding an acceleration of 3.267 m/s^2 would that be a correct approach, or is what i just laid out above incorrect?
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    Calculating Maximum Depth for a Sphere Dropped into Water

    oh i see, but how do i take that into account? the buoyant force still is non conservative right?
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    Calculating Maximum Depth for a Sphere Dropped into Water

    Homework Statement A small sphere 0.75 times as dense as water is dropped from a height of 11 m above the surface of a smooth lake. Determine the maximum depth to which the sphere will sink. Neglect any energy transferred to the water during impact and sinking. for clarity's sake, I'm...
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    I with a static fluids question

    haha I've learned to never blame the calculator, blame the user ;]. it was my own careless arithmetic error that caused me to get the wrong answer. when i got down to 27.5625 i subtracted 1.8 kg instead of subtracting (1.8*9.8)N and so i got an answer that was too large. thanks SO much for...
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    I with a static fluids question

    ok i did what you said. i obtained a v of .02756... and plugged that into Fb = 1000*(.02756...)*9.8, which gave me a Fb of 270.1125. I set this equal to mg and divided by 9.8 to get a final answer of 27.56. I then subtracted the 1.8 kg of wood and for some reason I'm wrong. Can you find my...
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    I with a static fluids question

    [SOLVED] i need help with a static fluids question Homework Statement A block of wood of 1.8 kg mass floats on water with 64% of its volume submerged. A lead block is placed on the wood and the wood is then fully submerged. Find the mass of the lead block. Homework Equations Fb =...
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