Recent content by ital_dj

Well I did the exam today so I'm done with physics for now... no need for the answer... I think I did pretty decent on the exam... no questions like that, though. Thanks everyone for the help.

well... what you told me is like a completely new language to me... thanks for the help, but i really don't understand it (i understand what you're saying but i don't know what to do with that)... is there a specific equation i can use? EDIT: I'm going to bed, my exam's early in the morning...

Sorry, I won't be able to help you as I'm studying for my physics exam tomorrow (grade 11)... but just an honest tip it's better to follow the guidelines when posting messages (the original question, relative formulas, and attempted solution)... the mods tend to like that better! Sorry again, I...

I'm no expert, I'm in grade 11 just like you but I'm a little better at this stuff than the rest... I'm not sure if I'm right, but use the V = 331 + .6(T) formula, and divide the first number (original), by the new number? And you might get a percentage? T is the temperature, it is also...

Okay, thanks.. but how do I put that into the question??

-1?? I don't know to be honest with you.

Homework Statement If an electroscope has a positive charge of 7.5 x 10^{-11}C, how many electrons have been removed from the electroscope, if it was originally neutral? (Answer: 4.7 x 10^{8}) Homework Equations I don't know :shy: The Attempt at a Solution Guys I seriously am...

Ok, thanks so far, but how, in general, do I know if the height is going to be positive or general, because I keep ending up with a negative number, but in most of my questions, the answer is a positive number.

I gave you the whole question, the only things I left out were: a) the position of the object; b) what sign should the focal length have; and d) the type and orientation of the image

But then when finding something like magnification, if the di or do is a negative, then the magnification (formula M= -di/do ) would be a positive number, which ends up being wrong because the image is supposed to be inverted, but ends up erect. EDIT: di and do is defined as distance

[SOLVED] General question about mirrors I'll give you a question as an example. My question to you isn't about solving the question, as you'll see below. Homework Statement A thumb of height 8cm is held in front of a concave mirror of focal length 10cm. The image formed is 12cm from the...

But still, how would I solve for d?

Kinetic Energy = 1/2mv^2 Gravitational Energy (Eg) = mg\Deltah

Homework Statement How much work is done by an Olympic triathlete who accelerates herself on her bicycle (combined mass of 105kg) from 5m/s to 10m/s Homework Equations W = mg\Deltad The Attempt at a Solution Tried solving for d, and plugging in.

Sorry, you're right... it should be divided by 2... I'll fix it right now. But, with the correct solution now, how did she arrive at that?