Recent content by itzela

I would appreciate any help i could get from anyone that has any idea at all to solve this equation because i have a upcoming exam tomorrow with the similar question like this and i really need help..please i would appreciate all kinds of help that i could get..i just can solve this equation as...

Ey Dude , I think u didnt get the function fully,it is [3(2^(2x+1))]+[5(2^(-x)] = 31 ^ means to the power of ...

I have a problem solving this equation for x - finding the maximum domains. 3(2^(2x+1)+5(2^(-x) )= 31 What I did first was to take the logarithim on both sides of the equation... to solve for x. But that apparently isn't a "logical" way to proceed. Any advice?

I was thinking of mounting a laser to a rotatable tripod and placing the tip of the laser on the focal point and rotating the tripod in order to produce parallel beams at different heights. But I'm not sure if the reflected beams will always come out parallel to the symmetry axis of the parabola...

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I'm sorry you're right, I was not very clear on how I proceeded. But i did indeed take the partial derivatives with respect to r and (theta), I didn't take the partialwith respect to "z" because z=z when converting between cartesian and cylindrical. The dot products were that of the inicial...

Hi =) I was given this problem on a test: a vector A = 2yi - Zj +3xk, was given in rectangular (cartesian) coordinates and I had to convert it to cylindrical coords. What I did to solve it was this: 1) A = 2rsin(theta)i - zj + 3rcos(theta)k 2) partial derivatives a) d/dr =...

Maybe by placing the light source directly on the focal point and varying the incident angle... or by manually simply changing the location of the light source (laser) so it passes through the focal point. Any better ideas?

I just thought about using a concave mirror and adjust the light source to always pass through the focal point of the mirror. That way all the reflected rays would come out parallel to the principal axis. Do you guys think it'll work?

I'm trying to find a mirror or a prism which would always reflect any incident light ray parallel to the a fixed axis (drawing attatched), no matter what the angle. I've found that right angle prisms reflect light parallel to the an axis, but I don't think works for rays coming at different...

Got it =) Thanks for pointing me in that direction.

I'm doing a diff eq problem and I got stuck on the part where I have to integrate [SIZE="4"]e^(x^2)dx. I tried using substitution but that didn't work :confused: ... any ideas?

Thanks Tom... i figured it out. It was actually quite simply, just a matter of separating the variables and differentiating.

any advice on how to start?

Hi Guys... I'm trying to learn diff.eq on my own and I'm stuck on a problem and I don't even know where or how to begin: the problem is: the pacemaker shown in the figure (first attatchment) is made up of an electric battery, a small capacitor, and the heart which functions like a resistance...