Recent content by izforgoat

this is weird hey so I seem to completely understand what I'm supposed to do... I set C1 = Q1/V and C2 = Q2/V At that point I see the obvious V=Q1/C1=Q2/C2 so I turn it into 2V=Q1/C1 +Q2/C2 this is where I diverge from what I think you guys are doing. so I have 2V(C1 + C2)= Q1+Q2 I do this...

kk think i got it but does the mass cancel out?

hmmm k so wow, i' not getting very far at all on this. since Tcos(x) = mg then Tcos(x) = 9.8 N and since T sin(x) = centripedalforce then Tsin= 1kg((4\pi^{2}r)/(.625^{2})) I'm slightly nervous proceeding since my next move would be to do a pythagoras of 9.8^{2} +...

Thanks a lot If you guys could check out the tetherba|| question I posted before this. That's the one I'm having the most problems without of the whole set. https://www.physicsforums.com/showthread.php?t=200278" thanks a lot, understanding this is really going to help me come monday.

so... in conclusion so it would be f = m * centripedal acceleration?

exact wording perhaps this is incorrectly phrased but the actual question is thespace shuttle is in orbit at400km above the Earth's surfce, and rounds the Earth every90 minutes. b) what is the weight of a 50kg person in the spaceshuttl? so I knew I had to havecentripedal...

Homework Statement If ashuttle has a centripedal accelerationof .54m/s2, what is the weight of a 50kg astronat in that shuttle? other info I don't know if I need. T= 5400sec r=400,000m Homework Equations fnet = ma I don't know if I am supposed to use \varpi= mg + ma but I don't...

changed tactic k so then I tried to do it from a bird's eye view (see my diagram) Since the two mirrors make a 60.5 degree angle that means the parallel light and mirror 2 also make a 60.5 degree angle. Since it comes in at that angle it bounces off mirror two, forming a 60.5 degree angle...

Homework Statement This is a concept/procedure question. I am playing teth3rbalI with a 1 kilogran ball and it is tied to a meterlong string. When I hit the ball it circles the pole at 1.6 Hz. Find the anglethat the string makes with thepole. Homework Equations a_{r}=v^{2}/r...

another try the other answer I came up with is 59 degrees

is this how it is? I'm trying to figure outhow this situation looks. If the diagram I drew is right then logically (since I haven't studied optics yet) if the angle between the mirrors were 90 degrees then then light would hit the other mirror perpendicularly as well, and the light wouldn't...

thank you

you could say that. But either way I don't think it would have much difference for this equation than the plug and chug. Right now I want to know if I am calculating everything else right. I assume I am.

I'm using a different value for this problem

thx a lot for that clarification. Still it doesn't make sense that its period would be 52 seconds here's my work. T(secs)^2 = (4(pi^2)(6,500,000^3 m))/((6.67*10^-7 N*m^2/kg^2)(5.98*10^24 kg)) are the units for T in seconds? was it alright that I changed km to m for the radius?