Weight of Astronaut on a Centripetal Shuttle

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The discussion revolves around calculating the weight of a 50 kg astronaut in a shuttle with a centripetal acceleration of 0.54 m/s². Participants clarify the difference between "actual weight," which is the gravitational force acting on the astronaut, and "apparent weight," which is what the astronaut feels due to other forces. It is emphasized that the apparent weight is effectively zero in orbit since the astronaut is in free fall with the shuttle. The correct approach involves using the formula f = ma to determine the actual weight based on centripetal acceleration. Understanding these concepts is crucial for solving related physics problems effectively.
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Homework Statement



If ashuttle has a centripedal accelerationof .54m/s2, what is the weight of a 50kg astronat in that shuttle?

other info I don't know if I need.
T= 5400sec
r=400,000m

Homework Equations



fnet = ma

I don't know if I am supposed to use \varpi= mg + ma but I don't think so

The Attempt at a Solution



so basically I'm just verifying if I should do f = ma and that will give me the weightofthe astronatu? thanks.
 
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By weight, is it meant the force with which the Earth is pulling the astronaut, or his/her weight relative to the shuttle? Do one thing, find both.

When we are standing or sitting on the Earth's surface, then we exert a force on the ground and the ground exerts a force back on us, which prevents us from going through the ground toward the centre of the earth. This we perceive as weight.
 
izforgoat, is that the exact phrasing of the question, or your interpretation? The phrasing "If a shuttle has a centripedal acceleration of .54m/s2" seems a bit odd.

The astronaut's "actual weight" is by definition the gravity force on the astronaut. The astronaut's "apparent weight" is what the astronaut feels. "Apparent weight" is the sum of all forces acting on an object but gravity. Gravity cannot be felt. (You don't feel gravity acting on you right now. You feel the chair you are sitting on pushing up on you with a force equal in magnitude to the gravitational force acting on you.)
 
exact wording

D H said:
izforgoat, is that the exact phrasing of the question, or your interpretation? The phrasing "If a shuttle has a centripedal acceleration of .54m/s2" seems a bit odd.

The astronaut's "actual weight" is by definition the gravity force on the astronaut. The astronaut's "apparent weight" is what the astronaut feels. "Apparent weight" is the sum of all forces acting on an object but gravity. Gravity cannot be felt. (You don't feel gravity acting on you right now. You feel the chair you are sitting on pushing up on you with a force equal in magnitude to the gravitational force acting on you.)

perhaps this is incorrectly phrased but the actual question is

thespace shuttle is in orbit at400km above the Earth's surfce, and rounds the Earth every90 minutes.

b) what is the weight of a 50kg person in the spaceshuttl?

so I knew I had to havecentripedal acceleration. I'm thinking I'm looking for apparent weight no?
 
No. I would say you are looking for actual weight. BTW, the astronaut's apparent weight has nothing to do with the orbital period unless the Shuttle happens to rotating about its center of mass at the orbital rate.
 
so... in conclusion

D H said:
No. I would say you are looking for actual weight. BTW, the astronaut's apparent weight has nothing to do with the orbital period unless the Shuttle happens to rotating about its center of mass at the orbital rate.

so it would be f = m * centripedal acceleration?
 
The apparent weight is zero, as the astronaut shares the motion of the shuttle. Actual weight would be mass*centripetal accn.
 
Thanks a lot

If you guys could check out the tetherba|| question I posted before this. That's the one I'm having the most problems without of the whole set.

https://www.physicsforums.com/showthread.php?t=200278"

thanks a lot, understanding this is really going to help me come monday.
 
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