Satellite period, which equation?

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The discussion revolves around calculating the orbital period of an object at a specified height above Earth's surface using two different equations. The first equation, T = (2πr)/√(gr), yields a period of approximately 5114 seconds, while the second equation, T² = (4π²r³)/(GM_earth), results in about 52 seconds, which seems illogical. Participants clarify that the value of G used in the calculations is incorrect, emphasizing that G should be 6.67 x 10^-11 N*m²/kg², not the erroneous value provided. The confusion stems from the use of a different gravitational constant, leading to significant discrepancies in the results. Accurate calculations require consistent and correct values for constants to ensure logical outcomes.
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Homework Statement



I'm looking for the period of an orbiting object a certain height from the Earth's surface, I am given this height. So I have the total radius of 6,5OO,OOO m, g = 9.81 m/s^2 and the mass of Earth = 5.98*10^24 kg

Please note that for this problem G is another constant than what it usually is.

Homework Equations



Here is where I am confused I do not know whether to use the T = (2\pir)/\sqrt{gr}

or the T^{2} = (4\pi^{2}r^{3})/(GM_{earth})

where G = 6.67*1O^-7

The Attempt at a Solution



K. So when I use the method of going with T = (2\pir)/\sqrt{gr}

I get about 5114 seconds for the period.

when I use T^{2} = (4\pi^{2}r^{3})/(GM_{earth})
I get 52.13584223 seconds, which doesn't logically seem right but since G is different I don't know.

does anyone know what the right method is?
 
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And your value for G is wrong. Though it's hard to really say until you put units on it.
 
thx a lot for that clarification. Still it doesn't make sense that its period would be 52 seconds here's my work.

T(secs)^2 = (4(pi^2)(6,500,000^3 m))/((6.67*10^-7 N*m^2/kg^2)(5.98*10^24 kg))

are the units for T in seconds? was it alright that I changed km to m for the radius?
 
Dick said:
And your value for G is wrong. Though it's hard to really say until you put units on it.

I'm using a different value for this problem
 
G=6.67*10^(-11)*N*m^2/kg^2. Note the exponent.
 
izforgoat said:
I'm using a different value for this problem

Is it an 'alternative universe' problem? Why would you use a different value for G? It's a 'universal constant'.
 
Dick said:
Is it an 'alternative universe' problem? Why would you use a different value for G? It's a 'universal constant'.

you could say that. But either way I don't think it would have much difference for this equation than the plug and chug. Right now I want to know if I am calculating everything else right. I assume I am.
 
The reason you getting 52 seconds is because you are putting in a value of G that is 10000 times too large. Other than that you are doing fine.
 
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thank you
 
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