Satellite period, which equation?

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Homework Help Overview

The discussion revolves around calculating the period of an orbiting object at a specified height above the Earth's surface, using given parameters such as height, gravitational acceleration, and the mass of the Earth. Participants are considering different equations for orbital period and questioning the appropriateness of the gravitational constant used in their calculations.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are comparing two different formulas for calculating the orbital period: one based on gravitational acceleration and the other derived from Kepler's third law. There are questions about the validity of the gravitational constant being used and its implications on the results.

Discussion Status

Some participants have provided clarifications regarding the gravitational constant and its significance in the calculations. There is ongoing exploration of the calculations and the implications of using different values for G, with no explicit consensus reached on the correct approach.

Contextual Notes

Participants are discussing the potential confusion arising from using a non-standard value for the gravitational constant, which may lead to significantly different results in the period calculation. There is also mention of unit conversions and their impact on the calculations.

izforgoat
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Homework Statement



I'm looking for the period of an orbiting object a certain height from the Earth's surface, I am given this height. So I have the total radius of 6,5OO,OOO m, g = 9.81 m/s^2 and the mass of Earth = 5.98*10^24 kg

Please note that for this problem G is another constant than what it usually is.

Homework Equations



Here is where I am confused I do not know whether to use the T = (2[tex]\pi[/tex]r)/[tex]\sqrt{gr}[/tex]

or the T[tex]^{2}[/tex] = (4[tex]\pi^{2}r^{3}[/tex])/(GM[tex]_{earth}[/tex])

where G = 6.67*1O^-7

The Attempt at a Solution



K. So when I use the method of going with T = (2[tex]\pi[/tex]r)/[tex]\sqrt{gr}[/tex]

I get about 5114 seconds for the period.

when I use T[tex]^{2}[/tex] = (4[tex]\pi^{2}r^{3}[/tex])/(GM[tex]_{earth}[/tex])
I get 52.13584223 seconds, which doesn't logically seem right but since G is different I don't know.

does anyone know what the right method is?
 
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And your value for G is wrong. Though it's hard to really say until you put units on it.
 
thx a lot for that clarification. Still it doesn't make sense that its period would be 52 seconds here's my work.

T(secs)^2 = (4(pi^2)(6,500,000^3 m))/((6.67*10^-7 N*m^2/kg^2)(5.98*10^24 kg))

are the units for T in seconds? was it alright that I changed km to m for the radius?
 
Dick said:
And your value for G is wrong. Though it's hard to really say until you put units on it.

I'm using a different value for this problem
 
G=6.67*10^(-11)*N*m^2/kg^2. Note the exponent.
 
izforgoat said:
I'm using a different value for this problem

Is it an 'alternative universe' problem? Why would you use a different value for G? It's a 'universal constant'.
 
Dick said:
Is it an 'alternative universe' problem? Why would you use a different value for G? It's a 'universal constant'.

you could say that. But either way I don't think it would have much difference for this equation than the plug and chug. Right now I want to know if I am calculating everything else right. I assume I am.
 
The reason you getting 52 seconds is because you are putting in a value of G that is 10000 times too large. Other than that you are doing fine.
 
  • #10
thank you
 

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