Hi Pure Anarchy. I'm a phy I student also. I took a shot at your problem. Did you get the same answer?
5m/s = initial acceleration.
0.8m = 80cm unit conversion
Vf = Vi +at
Vf = 0 (rest) + 5m/s * 0.8m = 4m/s
4m/s for 4 seconds = 16meters
Vf in the rough will be 0
0= 4m/s + a*2.5sec...
Homework Statement
First: My course has sig figs disabled. We are recording all that is shown in calculations. Its my instructor's choice, not mine. Please do not lecture on sig figs. I know already. ;)
Problem:
A person stands in a stationary canoe and throws a 4.85-kg stone with a...
The normal reaction force exerted on the refrigerator,
FN = mg - F sin 25.6 = 90.2x9.8 - 356x0.432
= 884 - 154 = 730 N.
Force of friction,
f = μ FN = 0.258 x 730
=188.3 N
along the horizontal surface, but opposite to displacement.
Work...
Homework Statement
Answer
Chapter 6, Problem 73 Cutnell & Johnson 7th edition
A 356 N force is pulling an 90.2-kg refrigerator across a horizontal surface. The force acts at an angle of 25.6 ° above the surface. The coefficient of kinetic friction is 0.258, and the refrigerator moves...
Stick & Bowling Ball
The angle of the stick with the floor is given at 30 degrees
The angle of the stick resting on the bowling ball is 60 degrees
The diameter of the bowling ball is given at 21cm so the radius is half that at 10.5cm
(.217kg)*9.8m/s = 2.1266N
.217kg * cos 60...
Homework Statement
A stick with a mass of 0.217 kg and a length of 0.435 m rests in contact with a bowling ball and a rough floor, as shown in the figure below. The bowling ball has a diameter of 21 cm, and the angle the stick makes with the horizontal is 30°. You may assume there is no...
Homework Statement
The (non-conservative) force propelling a 1.10 x 10(3)-kg car up a mountain road does 6.80 x 10(6) J of work on the car. The car starts from rest at sea level and has a speed of 22.0 m/s at an altitude of 1.90 x 10(2) m above sea level. Obtain the work done on the car by...
Homework Statement
A quarterback claims that he can throw the football a horizontal distance of 184 m. Furthermore, he claims that he can do this by launching the ball at the relatively low angle of 29.7 ° above the horizontal. To evaluate this claim, determine the speed with which this...
so if I understand you properly:
d= 4.99m/s * 3.59s - (.5)(-2.53m/s^2)(3.59)^2
I get 17.914--16.30 = 34.21
Am I using the deceleration properly? I haven't had physics in 30+ yrs
You are driving your car and the traffic light ahead turns red. You apply the brakes for 3.59 s, and the velocity of the car decreases to +4.99 m/s. If the car's deceleration has a magnitude of 2.53 m/s2, what is the car's displacement during this time?
I know Δd=Vi(Δt)+1/2at2. I am not...