Recent content by jacquelinem_00

Hey Adam! (Or anyone else!) I think I thanked you prematurely. From reading your response I thought I knew what I was doing, until I tried to finish the question, and realized I was still stuck. I took your advice and did everything. I fixed u=2 and set du=0. For the first part, I found...

Thank you so much Adam! You're great!

Homework Statement F(x,y) is defined by the integral (x,y) S [-2uv^2sin(u^2v)]du + [cos(u^2v) - u^2vsin(u^2v)]dv (2, pi) Express F(x,y) as a function of x and y, eliminating the integral sign. **Plus, I added the question as a bmp file, because I don't know how to write it...

Wait. I had meant that c1(y,z) = xy. What should I do to confirm this?

Hi there guys! Sorry I didn't respond and thank you in a while; I went on a bit of a vacation! So thank you Dick, for the hint. I think I got it, but I want to double check with you when what I've done... Here goes. p(x,y,z) = x(y+z) + c1(y,z) = xy + 1/2y^2 + c2(x,z) = xz + 1/2z^2 +...

Homework Statement A vector field is defined by F(x) = (y+z, x+y, x+z). Find the Jacobian and determine if the field is conservative in a finite region. If it is conservative, find the potential function. Homework Equations F = delta p AKA F = (upsidedown triangle) p The Attempt...

Hey guys! I got it! I know it took me a while, and you guys were probably just rolling your eyes at me, but I GOT IT! Yaaaay! Hooray for me! Calculus on a Saturday night! I just want to give my heartfelt thanks to you who have helped me. It means so much to me that you would reply so quickly...

" how does cos[t] + sin[t] = 1 become cos[t]^2 + sin[t]^2 = 1 ?? "cos[t] + sin[t] = 1 or also cos[t]^2 + sin[t]^2 = 1"" It doesn't, ha ha ha. I've been working (thinking about) this question for the past 2 weeks, and I guess I just made up some trig identities. Wouldn't it be nice if...

What else am I missing here? I've tried rearranging the equation, and I figure I have to raise everything to a power so that the cos[x] and sin[x] aren't raised to the power of (3/2). It has to be an even number power so that cos[pi] will remain -1. Any other hints?

When I substitute the x = a(cos[t])^(3/2) and y = a(sin[t])^(3/2) into the Left Hand Side of the equation, I get: (a(cos[t])^(3/2))^(2/3) + (a(sin[t])^(3/2))^(2/3) = a^(2/3) a^(2/3)(cos[t]) + a^(2/3)(sin[t]) = a^(2/3) cos[t] + sin[t] = 1 or also cos[t]^2 + sin[t]^2 = 1, which is the...

Homework Statement Parametrize the curve x^(2/3) + y^(2/3) = a^(2/3) in the standard counterclockwise sense. Homework Equations x^(2/3) + y^(2/3) = a^(2/3) Any trig identity... I was thinking cos(x)^2 + sin(x)^2 = 1 The Attempt at a Solution Because it has to be parameterized...