Now to work out at what voltage the air will breakdown and discharge.
The breakdown strength of air is 3 MV/m, right?
This maybe too simplified but can I do the following?
distance between plates = 0.02 m
breakdown voltage of air over 0.02 m is 3M * 0.02 = 60,000 V...
Yep figured the first bit.
It becomes a simple voltage divider circuit.
http://upload.wikimedia.org/wikipedia/en/f/f4/Impedance_Voltage_divider.png
k1=1.0006
k2=6.0
Vout = [Z2/(Z1+Z2)]*Vin
Zx = 1/j\omegaCx - Sub in for each Z
Cx = kx * ε0*A/d - Sub in...
Homework Statement
Hi everyone, I'm new here at posting but have found this forum very useful in the past. I have hit a snag with a capacitor problem... any thoughts?
Assume you have a parallel plate capacitor separated by one cm of air and one cm of a dielectric with a dielectric constant of...