Recent content by JamesW

using the Fg = Gm1m2/r^2 i have basically found gravity at around 8.87 N at 325000 m and then used this for the Ep=mgh calculation. This will not work, I could understand this. When i use the PE = -Gm1m2/r i get such a large negative number the sum of PE & Ek is negative i don't...

im wondering because i get different answers for potential energy Fg=Gm1m2/r^2 =((6.67e-11 N(m^2)/kg)(5.98e24 kg)(1.5e3 kg))/(6.705e6)^2 = 13308.24 N Ep= mgh = (13308.24 N)(325000 m) =4.325e9 J Ek=1/2mv^2 =1/2(1.5e3kg)(5.0e3 m/s)^2 = 1.875e10 J <<<<<<<<<<<<<<<...

Homework Statement Calculate the total energy of a geosynchronous satellite (one that orbits over a fixed spot) with a mass of 1.5 x 10^3 kg, orbiting Earth st a height of 325 km with an orbital speed of 5.0 x 10^3 m/s. Homework Equations Ek = 1/2 mv^2 Ep = mgh Fg = Gm1m2/r^2 or PE...

because Fs=(mu static)(Fn)

WHY IS Fn = Fgx/ mu static ?

Homework Statement A box with a mass of 22kg is at rest on a ramp inclined at 45 degrees to the horizontal. The coefficient of static friction is 0.78 determine the magnitude of the smallest force that can be applied onto the top of the box, perpendicular to the ramp if the box is to...