Box resting on an inclined plane

AI Thread Summary
To determine the smallest force applied perpendicular to a box resting on a 45-degree inclined plane, the static friction and gravitational forces must be balanced. The normal force (Fn) is calculated using the equation Fn = Fgx/mu static, where Fgx represents the gravitational force component along the ramp and mu static is the coefficient of static friction. This relationship arises because static friction (Fs) equals the product of the coefficient of static friction and the normal force, which must counteract the gravitational component to keep the box at rest. The discussion highlights the importance of understanding the balance of forces and the role of static friction in maintaining equilibrium on an incline. Accurate calculations are essential for determining the required applied force to prevent the box from sliding.
JamesW
Messages
6
Reaction score
0

Homework Statement



A box with a mass of 22kg is at rest on a ramp inclined at 45 degrees to the horizontal. The coefficient of static friction is 0.78

determine the magnitude of the smallest force that can be applied onto the top of the box, perpendicular to the ramp if the box is to remain at rest?

Homework Equations



F=ma

The Attempt at a Solution



F f (static friction) + Fgx = 0

F n = Fgy + F a

Fa = F n - Fgy

I have viewed a thread and to calculate F n (normal force) they divided Fgx/mu static. I was wondering why this was?
 
Physics news on Phys.org
WHY IS Fn = Fgx/ mu static ?
 
because Fs=(mu static)(Fn)
 
which is valid if friction _exactly_ cancels "g sin theta" ...
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Box and a Spring on on an inclined plane
Replies
11
Views
3K
Determining the angle while dealing with friction on an inclined plane
Replies
8
Views
3K
Applying Newtons Laws: Incline, static friction, kid on sled
Replies
8
Views
2K
What are the forces acting on a child pulling a wagon up an inclined hill?
Replies
3
Views
4K
Static & Kinetic Friction + An Applied Force on an Inclined Ramp
Replies
13
Views
4K
Why Is the Box Not Moving Despite Unbalanced Forces on an Inclined Plane?
Replies
4
Views
1K
How Far Can a Greased Watermelon Be Pulled Down an Inclined Plane?
Replies
5
Views
2K
3D Statics problem: Box on an inclined plane constrained by a rope
Replies
19
Views
2K
I have a hard time with kinematics involving inclined planes
Replies
4
Views
1K
Box sliding down an inclined plane
Replies
5
Views
3K

Hot Threads

Recent Insights

Back
Top