Recent content by jami8337

  1. J

    Solving a Problem with LPHW Radiator

    Okay here is what i have come up with: Temperature LPHW = θL Temperature Output = θO Heat Flow rate = Q Q=(θL-θO)/R Assuming no losses. The heat transferred from the LPHW alone determines the 'Radiator output' to the room. Therefore the rate of heat transfer will determine the rate of change...
  2. J

    Solving a Problem with LPHW Radiator

    Thanks for your help, I think i can draw both the block diagrams, but I am hitting a wall when having to derive the transfer function for the first one. This would be based on the energy balance equation i believe, but i am a bit lost trying to derive that. I have come up with: (TW-Ti)/R Where...
  3. J

    Solving a Problem with LPHW Radiator

    I am trying to solve a problem regarding an LPHW radiator, of which the heat output is controlled by adjusting the LPHW flow rate. The relationship between the flow rate and the radiator output can be approximated by a first order transfer function with a time constant of 1 minute. The heat...
  4. J

    Sampling Time Calculation for Bode Plots: Plant Comparison & ZOH Preceding

    Ah ok, so (1/2Π)*16rad/sec = 2.55 Hz Then Ts= 1/(2*fs) = 0.2 Thats great, thanks for all your help!
  5. J

    Sampling Time Calculation for Bode Plots: Plant Comparison & ZOH Preceding

    Ah yeah that's what I meant. So the highest frequency here would be about 17 rad/sec? Do i need to convert this into Hz in order to use it in the equation?
  6. J

    Sampling Time Calculation for Bode Plots: Plant Comparison & ZOH Preceding

    So if the Nyquist frequency is fs/2 and fs= 1/Ts, Ts = 1/2*Nyquist frequency ?
  7. J

    Sampling Time Calculation for Bode Plots: Plant Comparison & ZOH Preceding

    Ok, is the highest frequency then represented by fs/2 ?
  8. J

    How would you match up these Z-transforms?

    Sorry for the late response, my revision swapped to a different module. That's great thank you managed to solve it for the correct answer using that
  9. J

    Sampling Time Calculation for Bode Plots: Plant Comparison & ZOH Preceding

    Homework Statement In the figure, the Bode plots of a continuous-time plant (thin line) and of its discrete-time counterpart, representing the discrete-time operation of the plant preceded by a Zero Order Hold (ZOH) (bold line), are displayed. What is the Sampling time used? Homework...
  10. J

    How would you match up these Z-transforms?

    Homework Statement In Figure Q1b (on the next page), two plots display samples of the continuous-time signal uct(t) = sin(2πt) and two plots display samples of the continuous-time signal vct(t) = e −t sin(2πt). For each signal, the samples in the corresponding plots are obtained with two...
  11. J

    Digital control: Z transform

    Ok I think I may have done it, how does this look: function of initial line calculation: Then function of the second line: then the addition of the two to give a final answer: Is my working correct here? Or have i just fluked my way to the right answer haha
  12. J

    Digital control: Z transform

    Ok thanks for that, I am starting to get there now i managed to get the answer you go of (1/z^9)x((z^10-1)/z-1) for part A, however its the fact that the step goes up to 2, in part B that's throwing me, here's what I have done so far, am I on the right track? (Its a picture as it takes me...
  13. J

    Digital control: Z transform

    Ok I am literally getting nowhere with this, any other pointers?
  14. J

    Digital control: Z transform

    Ok thanks, i'll give that a go now and let you know how it goes! I know that's the answer as it is a question off a pass paper that our lecturer gave us along with a markscheme
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