Recent content by Jamie Bristow

I just finished my A levels in math's/physics. I decided to take a year out before I start an engineering degree. I'm looking for books to study on my work break's and any down time I get. I was looking at the 'Physics for Scientists and Engineers' by authors like Feynman and Serway. They can...

Thank you

Homework Statement When resolving forces on an inclined plane, can anyone explain to me why 1.2g in my pic is used as the hypotenuse? It looks intuitively like it should be the opposite or adjacent. Thanks for any help :) Homework EquationsThe Attempt at a Solution

Thank you so much. I feel like this would have been next to impossible without your guidance :oldbiggrin:

Ahh, I think I see. With 4.45A, 1023W is generated, and 23W is lost in the wires. and with 187A, 43,010W is being generated, with only 41962W being lost in the wires? So 4.45A is the more sensible choice?

Would I be right to move the IVf term over to the right-hand side of the equation, and then divide the left-hand side by this I to find Vf?

Oh my. I didn't anticipate this. So arranging for the quadratic formula I get -1.2(I)2 + 12(I) - 1000 = 0 and -1.2(I)2 + 230(I) - 1000 = 0 for 12V, the discriminant was a negative root, so 12V is impossible? for 230V, i got that I could equal 4.45...A, and 187.215...A

IVg - I2R - IVf = 0 They're all looking a lot like power equations now

Ah of course. This is suprisingly difficult to improvise having never seen it be done before. I'm tempted to say Vg - IR - IVf = 0 with IVf equalling 1kW

Sorry, I meant f, not p So: Vg - 1.2Ω - Vf = 0?

Ok so ill try this Vg-Vd-Vp=0? Just got a nice book out on KVL and KCL ill give this a read for an hour or so.

I don't get it? I'll just Find another way of doing it. I'm sorry you guys are probably frustrated with me, I have a learning disability and I get that a lot. cant you just give me the order of the formulas I need to use? because that is what is confusing me.

Ok so V0+Vg-V1-Vp=V0? or I could do V2/R to find powerfrom windmill?

for 230V - The voltage drop in the wire is 5.22V am i correct? so starting from the bottom-left gain of 230V minus 5.22V across the first wire minus 219.56V across the factory and minus 5.22V across the second wire

The course I am studying is mostly home study, we get one lesson a week on physics and one month to study for an exam. I have kind of neglected KVL since I know that most of the Exam is going to be using maxwells laws and drift velocities of elctrons and so on. I can understand this is a simple...