Why is 1.2g the Hypotenuse on an Inclined Plane?

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Homework Help Overview

The discussion revolves around the concept of resolving forces on an inclined plane, specifically questioning why a force represented as 1.2g is considered the hypotenuse in the context of vector resolution.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the reasoning behind the classification of 1.2g as the hypotenuse, expressing confusion about its relationship to the opposite and adjacent sides of the triangle formed by the inclined plane.
  • One participant suggests that when resolving a vector into components, the vector itself is the hypotenuse, indicating a distinction between the triangles involved.

Discussion Status

The discussion is ongoing, with some guidance provided regarding vector resolution. However, there is no explicit consensus on the original poster's understanding or the implications of the explanation given.

Contextual Notes

The original poster's inquiry suggests a potential misunderstanding of vector resolution in the context of inclined planes, indicating a need for further clarification on the topic.

Jamie Bristow
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Homework Statement


When resolving forces on an inclined plane, can anyone explain to me why 1.2g in my pic is used as the hypotenuse? It looks intuitively like it should be the opposite or adjacent.

Thanks for any help :)

IMG_20160228_141712072.jpg


Homework Equations

The Attempt at a Solution

 
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Whenever you resolve a vector into components that vector will be the hypotenuse. (Don't confuse the triangle of the inclined plane with the triangle you need when resolving a vector.)
 
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Thank you
 

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