Recent content by javii

I see, it is a mistake by me. Its just the height. Thanks

I_p= 1/12M(l^2+a^2)+M+d^2 I_p=1/12M*l^2+1/12*a^2+M+d^2 ?

For me, it is obvious that I have to divide 0.195 with 2, but I am not sure if 0.07 also have to be divided with 2 since the carton is skewed. So your are saying, that I also have to divide 0.07 with 2?

Homework Statement [/B] Homework Equations I have calculated the kinetic energy and the total moment of inertia. https://www.physicsforums.com/file:///C:/Users/javad/AppData/Local/Temp/msohtmlclip1/01/clip_image002.png The Attempt at a Solution I really don't know how to solve the problem...

So, the formula i have to use is: 1/3*m*(b^2+l^2)? and when i use that one i get which leads me to: so the angular velocity is 9.15 rad/s ?

Homework Statement Homework Equations The Attempt at a Solution Is it correct?

Thank you for your response.

Homework Statement Homework Equations ∑Mb = m*a*d The Attempt at a Solution Using the formula below i get: m*g*cos(0)*(0.07/2)-m*g*sin(0)*(195/2)=m*a*h And I get 3.52 m/s^2 Is it correct?

Will it then be: x1= y_1 = x_2 = y_2 = so: = in cartesian I get = 1.7134 +j1.7134 I really hope this is correct.

First of all, thank you for your feedback. I know that I am not done, as you say I need to find the answer in Cartesian form in Denmark (a+jb), that is why I am asking if i have to use the formula: which I am confirmed that I have to. And I can see, what you mean with the equal sign. Thank you.

Homework Statement The Attempt at a Solution The way i have simplified it: I do not know it is the way to do it. But if so, now I need to give the answer in cartesian form, and I think I need to use the formula: meaning it will look like: Anyone who can tell me if I am on the right...

Yes, that was what I meant. my bad its equal 25, meaning r = 5. I will try to read about atan2, to be honest I didn't knew about it. Thank you

Homework Statement Homework Equations r=sqrt(a^2+b^2) θ=arg(z) tan(θ)=b/a The Attempt at a Solution for a)[/B] finding the polar form: r=sqrt(-3^2+(-4)^2)=sqrt(7) θ=arg(z) tan(θ)=-4/-3 = 53.13 ° 300-53.13=306.87° -3-j4=sqrt(7)*(cos(306.87+j306.87) I don't know if my answer is correct...

Okay. Thank you very much. And yes there are more parts to the problem, i am trying to solve them now.

Yes i ment N=mg*cos(10)=1932.19 N (isolating for N) So I don't have to calculate for G_min? Meaning I can skip this part in the calculations?