Recent content by jayced

  1. J

    Calculating Force Exerted by Water on Container Bottom

    Homework Statement A container has a large cylindrical lower part with a long thin cylindrical neck. The lower part of the container holds 12.5 m3 of water and the surface area of the bottom of the container is 4.68 m2. The height of the lower part of the container is h1 = 3.30 m and the neck...
  2. J

    What percentage of the total mass of the pendulum is in the uniform thin rod?

    Homework Statement Christy has a grandfather clock with a pendulum that is 1.070 m long. (a) If the pendulum is modeled as a simple pendulum, what would be the period? Already solved (b) Christy observes the actual period of the clock, and finds that it is 1.20% faster than that for a...
  3. J

    Angular Momentum & Velocity: Solving Homework Q

    Ok, Still not getting th right answer: I did Inertia Arms I=1/3(3kg)(.65^2m)=.4225 kg*m^ X 2= .845 kg*m^2 Inertia Weight I=(3kg)(.22m)^2=.1452kg*m^2 X 2= .2904 kg*m^2 .845 kg*m^2+.2904 kg*m^2=1.13 kg*m^2 Once you have computed the change in moment of inertia, use the...
  4. J

    Angular Momentum & Velocity: Solving Homework Q

    Can someone give me an idea?
  5. J

    Angular Momentum & Velocity: Solving Homework Q

    "In I = 1/3mL^2, the L is length. I would write it as lowercase l to avoid confusion: LaTeX Code: I = \\frac{1}{3}ml^2 And the mass is 3kg... why would you think it would be otherwise? Note that you've computed the moment of inertia incorrectly as well - the units are wrong." Thanks...
  6. J

    Angular Momentum & Velocity: Solving Homework Q

    Homework Statement A student stands on a platform that is free to rotate and holds two dumbbells, each at a distance of 65 cm from his central axis. Another student gives him a push and starts the system of student, dumbbells, and platform rotating at 0.50 rev/s. The student on the platform...
  7. J

    What are the x and y components of the velocity of the CM of the two bodies?

    I'm still confused so if they are reversed can I ask what equation would I use to calculate x and y components?
  8. J

    What are the x and y components of the velocity of the CM of the two bodies?

    Homework Statement Body A of mass 3 kg is moving int he x+ direction with a speed of 14 m/s. Body B of mass 4 kg is moving in the -y direction with a speed of 7 m/s. What are the x and y-components of the velocity of the CM of the two bodies? The answer is (6m/s,-4m/s). Homework...
  9. J

    Explaination of Potential,Kinetic,and Total Enrgy involving going up a hill.

    Explanation of a cart rolling up a hill as it relates to Kinetic energy,total energy,and potential ener? For example let's saywe have a cart rolling up a hill: A)Why is the kinetic energy highest at the bottom of the hill ? B)Why is the total energy the same throughout? C)Why is the...
  10. J

    Net force problem pretty simple

    When on the ground, Ian's weight is measured to be 646 N. When Ian is on an elevator, his apparent weight is 711 N. What is the net force on the system (Ian and the elevator) if their combined mass is 1050 kg? I know that Fnet is the sum of all forces. I don't have any examples of this...
  11. J

    Potential Energy and Kinetic Energy Problem

    Wow ,thanx so much learningphysics you helped me plenty and this is the best kept secret. Good luck and know that its greatly appreciated.
  12. J

    Potential Energy and Kinetic Energy Problem

    60mins=1hr 24mins= 24min*60s=1440s 60mins* 4hr=240mins 60s=1min 240min*60s=14400 +1440s= total seconds =15840
  13. J

    Potential Energy and Kinetic Energy Problem

    It was one problem but my teacher refernced it for more questions. For the first part I calculated: A)What is the average angle of ascent the path makes with the horizontal?Theta=8 degre sin theta =2235m/16000m the 2235 came from 2746m-511m=2235 sin-1(0.139)=8.03 degrees B)What is their...
  14. J

    Potential Energy and Kinetic Energy Problem

    I got 0.705 when i divided the length of their path(16000m)/ the time it took them to get there 22680s,which equals 0.705m/s. That was their average speed in m/s.
  15. J

    Potential Energy and Kinetic Energy Problem

    We are getting there Learn, Can I find the horizontal velocity by doing my avg velocity of .705m/s times my time which is 22680s? Is my horizontal velocity equation v x t? Then in order to find my net velocity I add my horizontal and vertical velocities,Correct? But what does my net...
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